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posledela
3 years ago
12

Why is chemistry a science but alchemy was not?

Chemistry
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

d

Explanation:

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Br2(g) cl2(g)⇌2brcl(g) δh∘f for brcl(g) is 14. 6 kj/mol. Δs∘f for brcl(g) is 240. 0 j/mol
max2010maxim [7]

The Change in Gibb's free energy, ΔG for the reaction at 298K is; -56.92KJ.

<h3>Gibb's free energy of reactions</h3>

It follows from the Gibb's free energy formula as expressed in terms of Enthalpy and Entropy that;

  • ΔG = ΔH - TΔS

On this note, it follows that;

  • ΔG = 14.6 - (298× 0.24)

Hence, the Gibb's free energy for the reaction is;

  • ΔG = 14.6 - 71.52
  • ΔG = -56.92KJ

Remarks: The question requires that we determine the Gibb's free energy for the reaction at 298K.

Read more on Gibb's free energy;

brainly.com/question/13765848

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2 years ago
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The following chemical equation is not balanced: I2 + Na2S2O3 NaI + Na2S4O6 When this chemical equation is correctly balanced, w
marshall27 [118]

Answer:

The answer is B

4 0
3 years ago
The addition of perchloric acid to pure water causes the conductivity to _________.
Olin [163]
Adding perchloric acid to water would cause it's conductivity to increase.
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3 years ago
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Temperature is ____ related to the average kinetic energy of a gas.
Nastasia [14]

Answer:

directly

Explanation:

Temperature is defined as the average kinetic energy per particle of a gas, hence temperature and average kinetic energy are directly related meaning that if kinetic energy of a gas increases temperature will also increase.

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3 years ago
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If 4.12 l of a 0.850 m-h3po4 solution is be diluted to a volume of 10.00 l, what is the concentration of the resulting solution?
statuscvo [17]

The process in which the concentration of the solution is lessened  by the addition of water is said to be dilution and equation of dilution relates the initial concentration and volume of stock solution with the final concentration and volume of the solution.

Formula is given by:

C_{1}V_{1}=C_{2}V_{2}   (1)

where,

C_{1} is the initial concentration

V_{1} is the initial volume

C_{2} is the final concentration

V_{2} is the final volume

Now,

C_{1} = 0.850 M

V_{1} = 4.12 L

C_{2}  =?

V_{2} = 10.00 L

Substitute the give values in formula (1),

0.850 M\times 4.12L=C_{2}\times 10.00 L

C_{2} =\frac{0.850 M\times 4.12L}{10.00 L}

= 0.3502 M

Thus, the final concentration of theH_{3}PO_{4} solution = 0.3502 M












5 0
2 years ago
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