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const2013 [10]
3 years ago
15

Which conversion factor should you use first to calculate the number of grams of co2 produced by the reaction of 50.6 g of ch4 w

ith o2?
Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
8 0
Answer is: <span>1 mol CH</span>₄/<span>16,0 g CH</span>₄.
Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
m(CH₄) = 50,6g.
M(CH₄) = 16g/mol.
n(CH₄) = m(CH₄) ÷ M(CH₄) = 50,6g ÷16g/mol = 3,16mol.
n(CH₄) : n(CO₂) = 1:1.
nCO₂) = 3,16mol.
m(CO₂) = m(CO₂) · m(CO₂) = 3,16mol · 44g/mol = 139,15g.
M - molar mass.
n - amount of substance.
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The equilibrium constant, Kc, for the following reaction is 3.61×10-4 at 426 K. PCl5(g) PCl3(g) + Cl2(g) When a sufficiently lar
iogann1982 [59]

Answer:

the concentration of PCl5 in the equilibrium mixture = 296.20M

Explanation:

The concept of equilibrium constant was applied where the equilibrium constant is the ration of the concentration of the product over the concentration of the reactants raised to the power of their coefficients. it can be in terms of concentration in M or in terms of Pressure in atm.

The detaied steps is as shown in the attached file.

8 0
3 years ago
Can someone please help me with this?
yaroslaw [1]

Answer:

Lonic.an electron will be transferred from potassium to the chlorine atom

3 0
3 years ago
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True or False: Chlorine is a diatomic gas<br> True<br> False<br> Rewatch
Mashutka [201]
Answer:
true
Explanation: chlorine is an element that exists in nature as a diatomic molecule.
6 0
3 years ago
Indicate the hybridization of the central atom in (a) BCl3, (b) AlCl4-, (c) CS2, (d) GeH4
Tamiku [17]

Explanation:

(a) BCl3= sp² hybridization

(b) AlCl4- = sp³ hybridization

(c) CS2 = sp hybridization

(d) GeH4 = sp³ hybridization

5 0
3 years ago
If one starts with pure NO2(g) at a pressure of 0.500 atm, the total pressure inside the reaction vessel when 2 NO2(g) ⇌ 2 NO(g)
Anni [7]

Answer:

The equilibrium partial pressure of NO2 is 0.152 atm

Explanation:

Step 1: Data given

Initial pressure of NO2 = 0.500 Atm

Total pressure inside the vessel at equilibrium = 0.674 atm

Step 2: The balanced equation

2 NO2(g) ⇌ 2 NO(g) + O2(g)

Step 3: The initial pressures

pNO2 = 0.500 atm

pNO = 0 atm

pO2 = 0 atm

Step 4: The pressure at the equilibrium

pNO2 = 0.500 - 2x

pNO = 2x

pO2 = x

Total pressure = 0.674 = (0.500 - 2x) + 2x + x

0.674 = 0.500 + x

x = 0.174

pNO2 = 0.500 - 2*0.174 = 0.152 atm

pNO = 2x = 0.348 atm

pO2 = x = 0.176 atm

The equilibrium partial pressure of NO2 is 0.152 atm

4 0
3 years ago
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