1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LiRa [457]
3 years ago
6

Elements may have similar properties and we can use the periodic table to help us determine what they are. These three elements

are alike in many ways but they do not share ALL properties. What property do these elements NOT have in common?
Chemistry
2 answers:
Reil [10]3 years ago
8 0
They don’t have the Noble gases
Vika [28.1K]3 years ago
7 0

Answer:

same number of valence electrons

Explanation:

You might be interested in
Sodium hydrogen carbonate , also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid ind
user100 [1]

Answer:

3.8x10^{-1}gNaHCO_3

Explanation:

Hello,

This is a typical case in which the following chemical reaction is carried out:

HCl+NaHCO_3-->NaCl+H_2O+CO2

Since 50 mL of a 0.091M solution of HCl is employed, we perform the shown below stoichiometric calculation to find the sodium hydrogen carbonate grams that must be ingested by the woman:

m_{NaHCO_3}=0.050L*0.091\frac{molHCl}{L}*\frac{1molNaHCO_3}{1molHCl}*\frac{84gNaHCO_3}{1molNaHCO_3} =3.8x10^{-1}gNaHCO_3

Best regards.

3 0
3 years ago
11.39g PbCl2(s) 200.0 ML<br> Solve for m
german

Answer:

j/l

Explanation:

7 0
3 years ago
What do u mean by change in state of matter?define it.<br>​
ANEK [815]

Answer:

The mode of changing from one state of matter into another state and back to the former or original state is called change in state of matter .

hope it is helpful to you

7 0
3 years ago
Read 2 more answers
For a solution equimolar in HCN and NaCN, which statement is false? a. [H+] is larger than it would be if only the HCN were in s
balandron [24]

Answer:

option  (d) is false.

Explanation:

Acid dissociation equilibrium of HCN is represented as-

 HCN\rightleftharpoons H^{+}+CN^{-}

Acid dissociation constant, K_{a}, is represented as-

K_{a}=\frac{[H^{+}][CN^{-}]}{[HCN]}

where species inside third bracket represents equilibrium concentrations of respective species

So, evidently, presence of excess CN^{-} (or NaCN) in solution will combine with H^{+} to produce HCN. Hence H^{+} will be larger that it would be if only the HCN solution were present.

According to Le-chatlier principle, addition of HCN will shift equilibrium towards right and addition of NaCN will shift equilibrium towards left to keep constant K_{a} value at a particular temperature.

NaOH gives acid-base reaction with HCN to produce NaCN and water. So, addition of NaOH will increase concentration of CN^{-} and decrease concentration of HCN

6 0
3 years ago
3) How many grams are in 0.79 moles of HCI?<br> 1<br> UOL
snow_tiger [21]
Depending how you round and if you’re counting sig figs, it could be 28.8 or 29
3 0
3 years ago
Other questions:
  • A sample of 1.00 moles of oxygen at 50°C and 98.6 kPa occupies a volume
    15·1 answer
  • Which statement explains why sulfur is classified as a group 16 element
    12·1 answer
  • Which scientist won the nobel prize for discovering the electron?
    12·1 answer
  • Which of the following situations most likely indicates the lowest relative humidity? situation A situation B situation C situat
    8·2 answers
  • Is opposite poles repel each other why does the north end pf a compass point to the north pole
    14·1 answer
  • Which of the following is true regarding electrons?
    6·1 answer
  • What is the molar mass of CaCL2•2 H2O
    5·1 answer
  • Calculate the pH of the following?
    5·1 answer
  • Consider the reaction 2Al + 6HBr → 2AlBr3 + 3H2. If 12 moles of Al react with 12 moles of HBr, what is the limiting reactant?
    5·1 answer
  • A copper sulphate solution contained 0.100 moles of copper sulphate dissolved in 0.500 dm cubed of water. Calculate the mass of
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!