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2 years ago

5. What is the mole fraction of NaOH in an aqueous solution that contains 31.0 % NaOH by mass?

Chemistry

1 answer:

Liono4ka [1.6K]2 years ago

6 0

Answer:

16.8%

Explanation:

31% NaOH molar mass 40 gm

69% H2O molar mass 18 gm

1000 gm would be

310 gm NaOH or 310/40 = 7.75 moles

690 gm of H2O or 690/18 = 38.333 moles

7.75 / (7.75 + 38.333) = .168 mole fraction

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3 years ago

You perform a distillation to separate a mixture of propylbenzene and cyclohexane, and you obtain 2.9949 grams of cyclohexane (d

Romashka-Z-Leto [24]

Answer:

66.67%

Explanation:

From the given information:

mass of cyclohexane = 2.9949 grams

density of cyclohexane = 0.779 g/mL

Recall that:

Density = mass/volume

∴

Volume = mass/density

So, the volume of cyclohexane = 2.9949 g/ 0.779 g/mL

= 3.8445 mL

Also,

mass of propylbenzene = 1.6575 grams

density of propylbenzene = 0.862 g/mL

Volume of propylbenzene = 1.6575 g/ 0.862 g/mL

= 1.9229 mL

The volume % composition of cyclohexane from the mixture is:

$= (\dfrac{v_{cyclohexane}}{v_{cyclohexane}+v_{propylbenzene}})\times 100$

$= (\dfrac{3.8445}{3.8445+1.9229})\times 100$

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= 66.67%

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2 years ago