Answer:
??? why did you add hehehehe?
Explanation:
(3); try using the phrase "AN OX ate the RED CAT"
(anode=oxidation, reduction=cathode)
In balancing nuclear decay types of reaction, the same as balancing a chemical reaction, we use the number and the type of nucleons present for the decay reaction. Regardless of the type of decay, it should be that the total number of nucleons in the shole process should be conserved. For carbon-11, the decay equation would be as follows:
11/6 C --->11/5 B + 0/1β
It is an example of a positron emmision or a positive beta decay. It is a decay for neutron-poor nuclei where a proton is being transformed into a neutron and also emitting a positron that is high in energy.
Answer : The light rays are bent and refraction will occur - B.
Answer:
See figure 1
Explanation:
In this question, we have to find first the <u>chiral carbons</u> on 1,2-difluoro-1,2-dimethylcyclopentane. Carbons 1 and 2. Then, using the <u>Cahn–Ingold–Prelog priority rules</u>. We can draw all the stereoisomers. If we have 2 chiral carbons we will have (
) <u>4 isomers</u>. With this in mind we can have the R,R isomer; the S,S isomer; the S,R isomer, and the R,S isomer. We have to remember that:
<u>Priority 1 = "F"</u>
<u>Priority 2= "C"</u>
<u>Priority 3= "CH2"</u>
<u>Priority 4 = "CH3"</u>
I hope it helps!
