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Lilit [14]
3 years ago
15

How do you know flammability is a chemical property?

Chemistry
2 answers:
Reika [66]3 years ago
8 0
Because flammable objects have certain substances, you know that it is a chemical property. For example, cloth is flammable and has a certain substance that MAKES it flammable. This results in a chemical property.
Licemer1 [7]3 years ago
7 0
Paradox thinker is only partially correct. For combustion/for a fire to start, there must be a chemical reaction.
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Calculate the number of moles of Mg(NO3)2 consisting of 8.428 x 10^23 formula units of <br> Mg(NO3)2
bekas [8.4K]

Answer: 1.4 moles Mg(NO3)2

Explanation: Solution attached:

Convert the formula units of Mg(NO3)2 to moles using the Avogadro's number.

6 0
3 years ago
What is humidity?????????
Ivan

Answer:

it is the moisture in the air

Explanation:

if we buy a dehumidephire we see that it collets water from the air

4 0
3 years ago
Read 2 more answers
As the temperature of a reaction increases , it is expected that the reacting particles collide
Oxana [17]
It has been proven by Science that when the temperature of a reaction increases, the particles will gain energy and will collide faster and frequently.

Have a nice day! :)
6 0
3 years ago
What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen?
Anvisha [2.4K]

Answer:

= C3H4N

Explanation:

We are given; 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen.

We first calculate the number of moles of each element.

Carbon = 90g/12 g/mol

            = 7.5 moles

Hydrogen = 11 g/ 1 g/mol

                 = 11 moles

Nitrogen = 35 g/ 14 g/mol

               = 2.5 moles

The we get the mole ratio of the elements;

= 7.5/2.5 : 11/2.5 : 2.5 /2.5

= 3 : 4.4 : 1

= 3 : 4 : 1

Therefore;

The empirical formula will be; C3H4N

6 0
3 years ago
N204(0) + 2NO2(g)
user100 [1]

setup 1 : to the right

setup 2 : equilibrium

setup 3 : to the left

<h3>Further explanation</h3>

The reaction quotient (Q) : determine a reaction has reached equilibrium

For reaction :

aA+bB⇔cC+dD

\tt Q=\dfrac{C]^c[D]^d}{[A]^a[B]^b}

Comparing Q with K( the equilibrium constant) :

K is the product of ions in an equilibrium saturated state  

Q is the product of the ion ions from the reacting substance  

Q <K = solution has not occurred precipitation, the ratio of the products to reactants is less than the ratio at equilibrium. The reaction moved to the right (products)

Q = Ksp = saturated solution, exactly the precipitate will occur, the system at equilibrium

Q> K = sediment solution, the ratio of the products to reactants is greater than the ratio at equilibrium. The reaction moved to the left (reactants)

Keq = 6.16 x 10⁻³

Q for reaction N₂O₄(0) ⇒ 2NO₂(g)

\tt Q=\dfrac{[NO_2]^2}{[N_2O_4]}

Setup 1 :

\tt Q=\dfrac{0.0064^2}{0.098}=0.000418=4.18\times 10^{-4}

Q<K⇒The reaction moved to the right (products)

Setup 2 :

\tt Q=\dfrac{0.0304^2}{0.15}=0.00616=6.16\times 10^{-3}

Q=K⇒the system at equilibrium

Setup 3 :

\tt Q=\dfrac{0.230^2}{0.420}=0.126

Q>K⇒The reaction moved to the left (reactants)

8 0
3 years ago
Read 2 more answers
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