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Lilit [14]
3 years ago
15

How do you know flammability is a chemical property?

Chemistry
2 answers:
Reika [66]3 years ago
8 0
Because flammable objects have certain substances, you know that it is a chemical property. For example, cloth is flammable and has a certain substance that MAKES it flammable. This results in a chemical property.
Licemer1 [7]3 years ago
7 0
Paradox thinker is only partially correct. For combustion/for a fire to start, there must be a chemical reaction.
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Insulin is a protein that is used by the body to regulate both carbohydrate and fat metabolism. A bottle contains 375 mL of insu
Kitty [74]
Mass  =  Density  ×   Volume
          =  30.0 mg / mL  ×  375 mL
          =  11250 mg
          =  11.25 g

∴ the total mass of insulin in the bottle is 11.25 g (11250 mg)
4 0
3 years ago
crash course video about periodic table - The Periodic Table: Crash Course Chemistry #4 - write a reflection about this video
Stolb23 [73]

Answer:

I liked the video, it gave us lots of information about___. __ means/ is about.

Explanation:

7 0
3 years ago
What is the edge length of a face-centered cubic unit cell that is made of of atoms, each with a radius of 154 pm
gladu [14]

Answer:

The edge length of a face-centered cubic unit cell is 435.6 pm.

Explanation:

In a face-centered cubic unit cell, each of the eight corners is occupied by one atom and each of the six faces is occupied by a single atom.

Hence, the number of atoms in an FCC unit cell is:

8*\frac{1}{8} + 6*\frac{1}{2} = 4 atoms

In a face-centered cubic unit cell, to find the edge length we need to use Pythagorean Theorem:

a^{2} + a^{2} = (4R)^{2}     (1)

Where:

a: is the edge length

R: is the radius of each atom = 154 pm      

By solving equation (1) for "a" we have:

a = 2R\sqrt{2} = 2*154 pm*\sqrt{2} = 435.6 pm    

Therefore, the edge length of a face-centered cubic unit cell is 435.6 pm.   

I hope it helps you!

7 0
4 years ago
The percent composition of calcium is ?
DochEvi [55]

Answer: 40.1%

Explanation: The mass of calcium in this compound is equal to 40.1 grams because there's one atom of calcium present and calcium has an atomic mass of 40.1 . The molar mass of the compound is 100.1 grams. Using the handy equation above, we get: Mass percent = 40.1 g Ca⁄100.1 g CaCO3 × 100% = 40.1% Ca.

5 0
3 years ago
Help me with this question I’m kind of struggling
larisa86 [58]

All i know that we are HOOman

3 0
3 years ago
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