Answer:
Explanation:
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Answer:
4.06 g BaCl₂
Explanation:
Molarity (M) is given by this formula:
We are given M and L in this equation; we can solve for moles of BaCl₂ and use stoichiometry to convert this amount to grams.
First convert 50.0 mL to L:
Plug this value for L and 0.390 for M into the equation.
Solve for mol by multiplying .05 to both sides.
We have .0195 mol BaCl₂. Now let's use stoichiometry to calculate the amount of grams in .0195 mol BaCl₂.
The molar mass of BaCl₂ is 208.23 g so by using stoichiometry...
There are 4.06 g of BaCl₂ in this solution.