(20x^2-19x+3)/5x-1
(400x-19x+3)/5x-1
(381x+3)/5x-1
381x/5x-1 + 3/5x-1
(381/5-381) + (3/5x -3)
(76.2-381) + (3/5x -3)
304.8 + 3/5x-3
101.8 +3/5x
That's what I got. I'm not too sure if it helps though.
Answer:
x = -7/9
Step-by-step explanation:
The usual recommendation is to clear fractions first. Here, you can do that by multiplying both sides of the equation by 6.
6(-1/2(3x -4) +3x) = 6(5/6)
-9x +12 +18x = 5 . . . . . . . . . simplify
9x = -7 . . . . . . . . . . . . . . . . . subtract 12
x = -7/9 . . . . . .divide by 9
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Another way to do this is to eliminate parentheses first.
-3/2x +2 +3x = 5/6
3/2x = -7/6 . . . . . . . . . collect terms, subtract 2
x = (-7/6)(2/3) = -7/9 . . . . multiply by 2/3
Answer: 76 ft2
Step-by-step explanation:
Perimeter = 2 side length +base length
40 = 2s +12
Solving for s:
40-12 =2s
28 =2s
28/2=s
14ft =side
Since the line which bisects and isosceles triangles is at a right angle to the base we can use the Pythagorean Theorem to find the height (see attachment)
c^2 = a^2 + b^2
Where c is the hypotenuse of the triangle (in this case 14) and a and b are the other sides. (Base divided by 2 is one side, the other side is the height)
Replacing with the values given:
14^2= 6^2 + x^2
196 = 36 + x^2
196-36 = x^2
160 = x^2
√160 = x
x = 12.64 (height)
Area of an isosceles triangle = 1/2 x base x height
A = 1/2 x 12 x 12.64 = 76 ft2
Answer:
75?
Step-by-step explanation:
1/4 = 25
25 x 3 =75
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3/4=75