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Alik [6]
2 years ago
6

Rectangle with length 11 1/2 in. and width 8 in The area of this rectangle is____________

Mathematics
2 answers:
Phantasy [73]2 years ago
6 0

Answer:

Step-by-step explanation:

look, area = length x width

so that means that the area of this rectangle is

= 11 1/2 * 8

= 23/2 * 8

= 23 * 4 (simplified)

= 92 in^2

svetoff [14.1K]2 years ago
3 0

Answer:

92in.^{2}

Step-by-step explanation:

Area of a rectangle= L×W

If length= 11\frac{1}{2}in. and width= 8in.,

∴ Area = 11\frac{1}{2}in. × 8in.

           = \frac{23}{2} × \frac{8}{1} in.^{2}

           = (23 × 4) in.^{2}

           = 92in.^{2}

Hope this helps!!!

 

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Evaluate if a = 28 and b = -3.<br> a<br> 4 + b<br> = [?]
SVEN [57.7K]

Answer:

109

Step-by-step explanation:

(4)28+(-3)

4*28=112

112+(-3)

112-3

109

Hope this helps, LMK if its right

4 0
2 years ago
Express 3 log x^2 + 7 log x as a single log
miss Akunina [59]

Answer:

log x^13.

Step-by-step explanation:

Using the laws of logarithms

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= log x^6 + log x^7

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8 0
3 years ago
Find the perimeter of a square that is 3 3/4 inches on a side.
Dahasolnce [82]

perimeter would be s x 4

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 B is the correct answer

6 0
3 years ago
Subtract (x^2+3x-4) -(4x-2x^2-3)
Feliz [49]

Answer:

3 x^2 - x + -1

Step-by-step explanation:

Simplify the following:

-(4 x - 2 x^2 - 3) + x^2 + 3 x - 4

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--(2 x^2 - 4 x + 3) + x^2 + 3 x - 4

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2 x^2 - 4 x + 3 + x^2 + 3 x - 4

Grouping like terms, 2 x^2 + x^2 + 3 x - 4 x - 4 + 3 = (x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3):

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3 x - 4 x = -x:

3 x^2 + -x + (-4 + 3)

3 - 4 = -1:

Answer: 3 x^2 - x + -1

4 0
3 years ago
Costs related to rent, utilities, administration, equipment use and/or depreciation are called overhead.
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6 0
3 years ago
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