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bagirrra123 [75]
3 years ago
11

Carl wants to fill up his fish tank with water. To determine the amount of water that it will take to fill the tank, Carl needs

to calculate the ____________ of the tank. A) area B) volume C) perimeter D) lateral area
Mathematics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

The answer is B. Volume

Step-by-step explanation:

Finding the area of the tank would only show the size of one of the panals. The perimater is the length around one of the side panels of the tank. Lateral area is simmiler to the surface area, howerver it excludes the base and top. Volume is the only answer choice that calculates how much water will fill the tank. Volume can be found by multiplying the base multiplyed my the length multiplyed by the hight.

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There are no options, but I am pretty sure it would be

2x + 3x² ≠ 5x³

⭐ Please consider brainliest! ⭐

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Type the equation that shows the pattern among this set of ordered pairs.
Varvara68 [4.7K]
First find the slope between any two points:

\sf Slope=\frac{y_2-y_1}{x_2-x_1}

Where \sf (x_1,y_1),(x_2,y_2) are the two points

So calculating the slope:

\sf Slope=\frac{7-5}{2-1}=\frac{2}{1}=2

So the slope is \boxed{2}

And our equation will be in the format of \sf y=mx+b
where \sf m~ is~ the ~slope and \sf b ~is~the~y-intercept

So, now we have half of the equation:

\sf y= 2x+b

Now to calculate b, we can plug in a point \sf (x,y) and solve for b.

So

\sf y= 2x+b

Lets use the point
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5 0
4 years ago
Hector invests $800 in an account that earns 6.98% annual interest compounded semiannually. Rebecca invests $1000 in an account
Roman55 [17]
A=P (1+r/n)^nt

A= Total amount invested, P=principal amount, r=Interest rate, n=number of time in a year when the interest is earned (for annual, n=1; for semi-annual, n=2, ...), t = time in years

In the current scenario, case 1, n=2; case 2, n=1 and A1=A2, t1=t2
Therefore,
800(1+0.0698/2)^2t = 1000(1+0.0543/1)t
Dividing by 800 on both sides;
(1+0.0349)^2t = 1.25(1+0.02715)^t
(1.0349)^2t = 1.25(1.02715)^t
Taking ln on both sides of the above equation;
2t*ln (1.0349)= ln 1.25 + t*ln (1.02715)
2t*0.0343 = 0.2231+ t*0.0268
0.0686 t = 0.2231+0.0268 t
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Therefore, after 5.337 years or 5 years and approximately 4 months, their value of investments will be equal.

This value will be,
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3 0
3 years ago
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