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goldfiish [28.3K]
3 years ago
11

The necklace charm shown has two parts, each shaped like a trapezoid with identical dimensions. What is the total area, in squar

e millimeters, of the charm? Enter your answer in the box. mm² The figure is two identical trapezoids which share a base. The bases of the trapezoids are 25 millimeters and 32 millimeters. The height of the trapezoids is 15 millimeters
Mathematics
2 answers:
Aneli [31]3 years ago
7 0

Answer:

The answer is 855mm^2 i just took the k12 test

Step-by-step explanation:

pashok25 [27]3 years ago
3 0
The area of the trapezoid can be calculated through the equation, 
                               A = (b₁ + b₂)h / 2
where b₁ and b₂ are the bases and h is the height. Substituting the known values from the given, 
                              A = (25mm + 32mm)(15 mm) / 2 
                               A = 427.5 mm²
Since there are two trapezoids in the necklace, the area calculated is to be multiplied by two to get the total area. 
                        total area = (427.5 mm²)(2) 
                        <em>total area = 855 mm²</em>
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Answer:

The area will be increased by 72 feet.

Step-by-step explanation:

4 x 6 = 24

Now we have to double those lengths.

We know that 4 x 2 is 8 and 6 x 2 is 12.

So the new equation would be: 8 x 12 = 96

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2 years ago
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

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y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

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The percentage of the components bought from supplier C that are faulty = 88%

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The value, y, in dollars of an autographed basketball after x years can be represented by the function y=4000(1.05)x.
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Answer:

I took the test!!

Step-by-step explanation:

Pit this in your calculator exactly like this 4,000(1.05)^5 and you get the answer 5,105.12625. So round your answer to the nearest dollar, which is 5,105.

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