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anygoal [31]
3 years ago
6

Let a and b be real numbers were a≠ b ≠ 0. Which of the following functions could represent the graph below?

Mathematics
1 answer:
wlad13 [49]3 years ago
8 0

Answer:

A

Step-by-step explanation:

where the graph

WHERE THE GRAPH???

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Help me with number three please
Alexxandr [17]
Y2-Y1/X2-X1 = 7-22/1-4 = -15/-3 = 5
y=5x+ 0
3 0
3 years ago
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What is the mean of -9,-5,-4,-4,-2,0,1,2,3,5
IrinaK [193]

Answer: - 1.3

Step-by-step explanation: I believe that it's -1.3 if you're referring to the arithmetic mean.

(1) Take the sum of -9, -5, -4, -4, -2, 0, 1, 2, 3, 5 and simplify it to -13

(2) Count the number of terms in the data set.

{-9, -5, -4, -4, -2, 0, 1, 2, 3, 5}

{1, 2, 3, 4, 5, 6, 7, 8, 9, 10} - The number of terms in the data set is <u>10.</u>  

(3) Divide the sum by the number of terms and simplify.

-13 / 10 = -1.3 (simplified)

8 0
3 years ago
The diameter of a circle is 20 centimeters. What is the radius?
Mama L [17]

Answer:

10

Step-by-step explanation:

radius is the middle point of a circle, therefore divide it in half.

8 0
3 years ago
If y=(x^2-4)^5(3x+4)^4
alexira [117]

Answer:

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

Step-by-step explanation:

y=(x^2-4)^5(3x+4)^4

y'=[\frac{d}{dx}(x^2-4)^5](3x+4)^4+(x^2-4)^5[\frac{d}{dx}(3x+4)^4]

y'=10x(x^2-4)^4(3x+4)^4+(x^2-4)^5(12(3x+4)^3)

y'=10x(x^2-4)^4(3x+4)^4+12(x^2-4)^5(3x+4)^3

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

5 0
2 years ago
SOLVE ALL THESE EQUATION BY USING THE METHOD SUBSTITUTION ALGEBRAICALLY HERE'S ARE ALL THE EQUATION:
pav-90 [236]

Answer:

See below ~

Step-by-step explanation:

<u>Question 1</u>

  • -7x - y = -1
  • y = 8x + 16

⇒ -7x - (8x + 16) = -1

⇒ -7x - 8x - 16 = -1

⇒ -15x = 15

⇒ x = -1

⇒ y = 8(-1) + 16 = 8

⇒ Solution = <u>(-1, 8)</u>

<u></u>

<u>Question 2</u>

  • 3x + 4y = 0
  • y = -3x - 18

⇒ 3x + 4(-3x - 18) = 0

⇒ 3x - 12x - 72 = 0

⇒ -9x = 72

⇒ x = -8

⇒ y = -3(-8) - 18 = 6

⇒ Solution = <u>(-8, 6)</u>

<u>Question 3</u> (not clear)

<u>Question 4</u>

  • -8x - 7y = 0
  • y = 6x

⇒ -8x - 7(6x) = 0

⇒ -8x - 42x = 0

⇒ -50x = 0

⇒ x = 0

⇒ y = 6(0) = 0

⇒ Solution = <u>(0, 0)</u>

<u>Question 8</u>

  • 2x - 6y = -14
  • y = -5x - 19

⇒ 2x - 6(-5x - 19) = -14

⇒ 2x + 30x + 114 = -14

⇒ 32x = -128

⇒ x = -4

⇒ y = -5(-4) - 19 = 1

⇒ Solution = <u>(-4, 1)</u>

3 0
2 years ago
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