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3 years ago

12

the Indian Ocean is 2/10 of the area of the world's oceans. what fraction represents the area of the remaining oceans that make

up the world's oceans? write in simplest form.

1 answer:

Shtirlitz [24]3 years ago

4 0

8/10 or 4/5 is what makes up the remaining oceans

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There are six muffins in a package. How many packages will be needed to feed 48 people if each person has two muffins

lawyer [7]

4 because 48 divided 2 equals 24 adn 24 divided by 6 equals 4

6 0

3 years ago

Read 2 more answers

Solve for p, I don't know what else to add but yeah<br> solve for p?<br> Also explain

Charra [1.4K]

Answer:7

Step-by-step explanation:

6p-4+7p+3=90

13p-1=90

13p=91

p=7

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3 years ago

If sin=3 by 5 and cos =4 by 5 find tan

Afina-wow [57]

Answer:

<h3>3/4</h3>

Step-by-step explanation:

$tan = \frac{sin}{cos }$

<h3> =3/5/4/5</h3>

=3/5 × 5/4

=15/20

<h3> </h3><h3> =3/4</h3>

7 0

3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

3 years ago

I need work shown please help (I will mark as brainliest)

JulsSmile [24]

Answer:

for the second page the answer is B the third page is D

Step-by-step explanation:

15 x 10 x 8 = 1200

24 + 25 (49 + 64 + 55)= 168

Hope this helps
i could only give you two of them
Brainliest plz
Ask questions if wrong

7 0

3 years ago