Question 11a)
We are given side BC equals to side CE and angle CBA equals to angle CED
We also know that angle ACB equals to angle ECD are equal (opposite angles properties)
We have enough information to deduce that triangle ABC and triangle CDE are equal by postulate Angle-Side-Angle (ASA)
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Question 11b)
We are given side AB equal to side ED, side BC equals to side EF, and side AC equals to side DF
We have enough information to deduce that triangle ABC and triangle DEF congruent by postulate Side-Side-Side (SSS)
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Question 11c)
We are given side AC equals to side DF, angle ABC equals to angle DEF, and angle BAC equals to angle EDF
We have enough information to deduce that triangle ABC congruent to triangle DEF by postulate Angle-Side-Angle (ASA)
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Question 11d)
We do not have enough information to tell whether this shape congruent or not
Since they are mutually exclusive, P(8 or >12) = P(8) + P(>12) = 1/16 + 4/16 = 5/16
You would draw 48 counters and 18 counters which would be 66 counters in total. The picture is 1 of the sixteens and 1 of the nines. Sorry, if I misunderstood or got it wrong, I tried. If you don't understand something or I left out something, tell me in the comments.
Divide both the numerator and the denominator by 4, so 12/20 becomes 3/5.
