Answer:
idk
Step-by-step explanation:
Answer:
162
Step-by-step explanation:
( -a ) ( b ) ( -a + b )
-6 ( 3 ) ( -6 + -3 )
-6 ( 3 ) ( -9 )
- 18 ( -9 )
162
Answer: 17.75
Step-by-step explanation:
The interquartile range(IQR) is the 3rd quartile - the 1st quartile.
How to get quartiles:
First get the median:
3.5, 10.4, 16, 21.7, 27.7
10.4, 16, 21.7
16
Then find the median of the first half of data(3.5, 10.4)
(3.5+10.4)/2 = 6.95
Then find the median of the last half of data(21.7, 27.7)
(21.7+27.7)/2 = 24.7
Then to get the IQR subtract 6.95 from 24.7 to get 17.75
Hope it helps <3
Answer:
i think it might be 118.4
Step-by-step explanation:
Answer:
The final position is 5 feet below the back of the truck
Step-by-step explanation:
* Lets explain how to solve the problem
- A crane lifts a pallet of concrete blocks 8 feet from the back of
a truck
- The crane lowers the pallet 13 feet after the truck drives away
- Assume that the zero level of the position of the ballet of concrete
blocks is the back of the truck
∵ The crane lifts the pallet of concrete blocks 8 feet from the back
of the truck
- That means it take the pallet from zero to 8
∴ The height of the pallet of concrete blocks is 8 feet over
the starting position
∵ The crane lowers the pallet of concrete blocks 13 feet
- That means the crane lower the pallet from the height 8 and
lift it down 13 feet, so we must to take out from the 8 feet the
13 feet to find the final position of the pallet of concrete blocks
∴ The pallet position is ⇒ 8 - 13 = -5
∴ The position of the pallet of concrete blocks is 5 feet below the
starting position which is the back of the truck
* The final position is 5 feet below the back of the truck
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