3Cl2 + 2Al ---> 2AlCl3
you're pretty much trying to find the lcm to balance the equation
aka you have 2 Cl's on one side and 3 on the other...
lcm=6 so put a 3 before Cl2 and a 2 before AlCl3 (since thats one big compound you cant divide it)
now since Al has 2 on one side, you need to make sure it has the same amound on the other... so 3, 2 --> 2
Answer:
The answer to your question is 0.34 M
Explanation:
Data
[Sr(OH)₂] = ?
Volume of Sr(OH)₂ = 35.6 ml or 0.0356 l
[HBr] = 0.0445 M
Volume of HBr = 0.549 l
Balanced chemical reaction
2HBr + Sr(OH)₂ ⇒ SrBr₂ + 2H₂O
Process
1.- Calculate the moles of HBr
Molarity = moles / volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = 0.0445 x 0.549
= 0.0244
2.- Calculate the moles of Sr(OH)₂ using the coefficients of the balanced reaction
2 moles of HBr ----------------------- 1 mol of Sr(OH)₂
0.0244 moles ----------------------- x
x = (0.0244 x 1) / 2
x = 0.0122 moles of Sr(OH)₂
3.- Calculate the concentration of Sr(OH)₂
Molarity = 0.0122/ 0.0356
-Simplification
Molarity = 0.34
Answer:
Option C. By increasing the temperature
Explanation:
From the graphical illustration above, we see clearly that the volume and temperature of the gas are directly proportional. This implies that as the temperature increases, the volume will also increase and as the temperature decreases, the volume will also decrease. This can further be explained by using the ideal gas equation as shown below:
PV = nRT
P is the pressure.
V is the volume.
n is the number of mole.
R is the gas constant.
T is the temperature.
PV = nRT
Divide both side by P
V = nRT/P
Since n and P are constant, the equation above becomes:
V & T
V = KT
K is the constant.
The above equation i.e V = KT implies that:
As T increases, V will also increase and as T decreases, V will also decrease.
Considering the question given above,
The volume of the gas can be increased if the temperature is increased.
The molarity is 3.50 M/L.
Explanation:
Molarity is found to know the amount of the solute ions present in the given volume of solution. So we determine it using the ratio of the moles of solute to the volume of the solution.
As here the weight of the solute which is hydrochloric acid is given as 17g, so we need to find the moles of it. This can be done by dividing the given amount of HCl with the molecular weight of HCl.
Molecular weight of HCl = 1.01 + 35.45 = 36.46 g/mol
So the number of moles of HCl present here will be
So, 0.466 moles of HCl is present in the solution.
Thus, the molarity is 3.50 M/L.
