Balance the following reaction... _P4010 +_ H2O →_H3PO4
1 answer:
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<u>Answer:</u> The mass of required is 14.37 g
<u>Explanation:</u>
Molarity is calculated by using the equation:
......(1)
We are given:
Molarity of iron (II) sulfate = 1 M
Volume of solution = 200 mL = 0.200 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
The chemical equation for the reaction of FeO with sulfuric acid follows:
By stoichiometry of the reaction:
If 1 mole of iron (II) sulfate is produced by 1 mole of FeO
So, 0.200 moles of iron (II) sulfate will produce = of FeO
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
We know, molar mass of = 71.84 g/mol
Putting values in above equation, we get:
Hence, the mass of required is 14.37 g