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lyudmila [28]
3 years ago
6

Is 2AI + 3O2 = 2AI2O3 balanced or unbalanced?

Chemistry
1 answer:
Luba_88 [7]3 years ago
3 0
This equation is balanced.
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if the gas pressure exerted by a gas at 45 degrees celsius in a volume of 1.944 ATM, how many moles of gas are present?​
Firdavs [7]
If the.pressure exerted by a gas at [math]25^{\circ} \mathrm{C}[/math] in a volume of 0.044 L is 3.81 atm, how many moles of gas are present
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One example of a thermal conductor
Harlamova29_29 [7]
Metal radiator. When hot water flows through the coils of the radiator , the metal heats up quickly by conduction and then radiates thermal energy into the surrounding air.


Answer: Metal radiator
6 0
2 years ago
Read 2 more answers
What should each experiment only have one of?
Ket [755]

Answer: varriable

Explanation:meaning one element, feature or factor able to change

3 0
2 years ago
When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from
IgorLugansk [536]

The question is incomplete, here is the complete question.

When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from a mixture of 3.0g Ag and 3.0g S_8.

Answer : The mass of silver sulfide is produced from a mixture is 3.44 grams.

Explanation : Given,

Mass of Ag = 3.0 g

Mass of S_8 = 3.0 g

Molar mass of Ag = 107.8 g/mole

Molar mass of S_8 = 256 g/mole

Molar mass of Ag_2S = 247.8 g/mole

First we have to calculate the moles of Ag and S_8.

\text{ Moles of }Ag=\frac{\text{ Mass of }Ag}{\text{ Molar mass of }Ag}=\frac{3.0}{107.8g/mole}=0.0278moles

\text{ Moles of }S_8=\frac{\text{ Mass of }S_8}{\text{ Molar mass of }S_8}=\frac{3.0g}{256g/mole}=0.0117moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

16Ag(s)+S_8(s)\rightarrow 8Ag_2S(s)

From the balanced reaction we conclude that

As, 16 mole of Ag react with 1 mole of S_8

So, 0.0278 moles of Ag react with \frac{0.0278}{16}=0.00174 moles of S_8

From this we conclude that, S_8 is an excess reagent because the given moles are greater than the required moles and Ag is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Ag_2S

From the reaction, we conclude that

As, 16 mole of Ag react to give 8 mole of Ag_2S

So, 0.0278 moles of Ag react to give \frac{0.0278}{16}\times 8=0.0139 moles of Ag_2S

Now we have to calculate the mass of Ag_2S

\text{ Mass of }Ag_2S=\text{ Moles of }Ag_2S\times \text{ Molar mass of }Ag_2S

\text{ Mass of }Ag_2S=(0.0139moles)\times (247.8g/mole)=3.44g

Therefore, the mass of silver sulfide is produced from a mixture is 3.44 grams.

4 0
3 years ago
state the behaviour of equilibrium , of ammonia is removed from the reaction mixture . Explain your answer
OLEGan [10]

Equilibrium

N₂(g) + 3H₂(g) ⇔ 2NH₃(g)

If the concentration of the reactants is added, the system will reduce the concentration of the reactants by shifting towards the products and vice versa if the concentration of the reactants is decreased the system will shift towards the reactants.

ammonia is removed from the reaction mixture ⇒ it means the ammonia is reduced then the equilibrium shifts to the right

5 0
2 years ago
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