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Radda [10]
2 years ago
6

The radius of an atom of element X is 1.2x10m The radius of the centre of the atom is 1/10000 the radius of the atom Calculate t

he radius of the centre of an atom of element X
Chemistry
1 answer:
Alika [10]2 years ago
8 0

Answer:

radius=1.2x10^{-3}m

Explanation:

Hello,

Based on the given information, the radius is computed via:

radius=1.2x10m*\frac{1}{10000}=1.2x10^{-3}m

By assuming that the radius of the element is 1.2x10m, nevertheless, that is a pretty much big radius for an atom in meters, maybe a power is missing, but you can modify it by just including it in the aforesaid formula.

Best regards.

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2 years ago
How many grams of helium must be released to reduce the pressure to 65 atmatm assuming ideal gas behavior? Express the answer in
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The question is incomplete, here is the complete question:

How many grams of helium must be released to reduce the pressure to 65 atm assuming ideal gas behavior. Note : 334-mL cylinder for use in chemistry lectures contains 5.209 g of helium at 23°C.

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<u>Explanation:</u>

We are given:

Mass of helium in the cylinder = 5.209 g

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

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P = Pressure of the gas  = 65 atm

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w = Weight of the gas = ?

M = Molar mass of helium gas  = 4 g/mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

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Putting values in above equation, we get:

65atm\times 0.334L=\frac{w}{4g/mol}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 296K\\\\w=\frac{65\times 0.334\times 4}{0.0821\times 296}=3.573g

Mass of helium released = (5.209 - 3.573) g = 1.636 g = 1.6 g

Hence, the mass of helium released is 1.6 grams

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did that help

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