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Radda [10]
3 years ago
6

The radius of an atom of element X is 1.2x10m The radius of the centre of the atom is 1/10000 the radius of the atom Calculate t

he radius of the centre of an atom of element X
Chemistry
1 answer:
Alika [10]3 years ago
8 0

Answer:

radius=1.2x10^{-3}m

Explanation:

Hello,

Based on the given information, the radius is computed via:

radius=1.2x10m*\frac{1}{10000}=1.2x10^{-3}m

By assuming that the radius of the element is 1.2x10m, nevertheless, that is a pretty much big radius for an atom in meters, maybe a power is missing, but you can modify it by just including it in the aforesaid formula.

Best regards.

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How many atoms of Kr (Krypton) are in a balloon that contains 2.00 mol of Kr? (4)
Svetllana [295]

Answer:

atoms= 1.204x10^{24}atoms

Explanation:

Hello!

In this case, according to the Avogadro's number, it is possible to compute the atoms of Kr in 2.00 moles as shown below:

atoms=2.00mol*\frac{6.022x10^{23}atoms}{1mol} \\\\atoms= 1.204x10^{24}atoms

Best regards!

4 0
3 years ago
The freezing point of a solution the freezing point of the pure solvent
babymother [125]

Answer:

This means that a solution must be cooled to a lower temperature than the pure solvent in order for freezing to occur.

Explanation:

5 0
3 years ago
Read 2 more answers
How much energy (in Joules) is required to convert 129 grams of ice at −23.0 °C to liquid water at 18.0 °C?
Karo-lina-s [1.5K]

Answer:

The energy that is required for the process is:

6230.7 J + 42957 J + 9715.2 J = <u>58902.9 joules</u>

Explanation:

This is a calorimetry problem:

Q = m . C . ΔT

Q = heat; m = mas; C is the specific heat and

ΔT = Final T° - Initial T°

Q = C lat . m

Q = Heat

m = mass

C lar = Latent heat of fusion

First of all we calculate the heat for ice, before it takes the melting point. (from -23°C  to 0°C)

Q = 129 g . 2.10 J/g°C . (0°C - (-23°C)

Q = 129 g . 2.10 J/g°C . 23°C → 6230.7 joules

Then, the ice has melted. To be melted and change the state it required:

Q = C lat . m

Q = 333 J/°C . 129 g → 42957 joules

And in the end, we have water that changed its T° from O°C to 18°C

Q = 129 g . 4.184 J/g °C . (18°C - 0°C)

Q = 9715.2 Joules

The energy that is required for the process is:

6230.7 J + 42957 J + 9715.2 J = 58902.9 joules

5 0
3 years ago
What is the significance sodium hydroxide and hydrochloric acid
hammer [34]

Answer:

They are a base and an acid,  so they neutralize each other.

Explanation:

Sodium hydroxide is a strong base. Hydrochloric acid is a strong acid.

They react with (neutralize) each other to form a salt (sodium chloride) and water.

NaOH + HCl ⟶ NaCl + H₂O

5 0
3 years ago
Which of these is a chemical property?<br><br> boiling point<br> odor<br> ability to rust<br> color
NISA [10]

Answer:

ability to rust

Explanation:

i'm like 90% sure thats correct

6 0
3 years ago
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