3 years ago

How do you solve for y in the equation: x/y = y - 6

Mathematics

1 answer:

I am Lyosha [343]3 years ago

7 0

Answer:

x= y^2 -6y

Step-by-step explanation:

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zhannawk [14.2K]

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2 years ago

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$x^2+y^2-8x-6y+24=0\quad|-24\\\\(x^2-8x)+(y^2-6y)=-24$

Complete the square:

$x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2$

And we have:

$(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\
(x-4)^2+(y-3)^2-16-9=-24\\\\(x-4)^2+(y-3)^2-25=-24\quad|+25\\\\\boxed{(x-4)^2+(y-3)^2=1}$

So the answer is C (the same left side of equation).

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3 years ago

Find the height of a triangle if the base measures 6 inches and the area is 15 square inches. Use the formula for the area of a

harkovskaia [24]

Answer:

height equals 5 inches

Step-by-step explanation:

base = 6

area = 15

area = 1/2(6)h

15= 3h

5=h

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2 years ago