The second leftover expression is not o(a+b). It is 6(a + b). I have attached the correct question to depict that.
Answer:
The equivalent expressions are;
8a + 2 and 6a + 6b
Step-by-step explanation:
The two leftover expressions are given as;
2(4x + 1) and 6(a + b)
In algebra, equivalent expressions are simply those expressions which when simplified, give the same resulting expression as the initial one.
Thus simply means expanding or collecting like times to make it clearer.
Now, in our question, like terms have already been collected. This means that to find an equivalent expression, we will just expand the bracket.
Thus;
2(4x + 1) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;
8x + 2
Similarly,
6(a + b) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;
6a + 6b
Thus;
The equivalent expressions are;
8a + 2 and 6a + 6b
Heya user
we have
7x - 6y and x + y
according to the question
( 7x - 6y ) + ( x + y )
→ 7x - 6 y +x + y
→ 8x - 5y
Hope This helps you
Let the three numbers be x, y and z respectively, then
x + y + z = 62 . . . (1)
y = x - 4 . . . (2)
z = 4x . . . (3)
The above three expressions could be used to represent the numbers.
Solving the three equations, putting (2) and (3) into (1) gives
x + x - 4 + 4x = 62
6x - 4 = 62
6x = 62 + 4 = 66
x = 66/6 = 11
x = 11.
y = 11 - 4 = 7
z = 4(11) = 44
x = 11, y = 7, z = 44.
Step-by-step explanation:
18:27
=18/27
=2/3 or 2:3
Step-by-step explanation:
given f(x) = 2/x and g(x) = 2/x
f(g(x)) = 2/(g(x)) = 2/2/x = x/2 × 2 = x
g(f(x)) = 2/(f(x)) = 2/2/x = x/2 × 2 = x
therefore they are inverses
since f(g(x)) = g(f(x)) = x.