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ollegr [7]
4 years ago
14

Is this statement true? (x/y)-z=x/(y-z)

Mathematics
1 answer:
Bond [772]4 years ago
5 0
False, this statement is not true, because if you change the parenthesis, it means that you will do that thing first (PEMDAS)
Therefore, the sstatement is false, because the answers will be completely different, 

hope this helps
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Help please! <br> find the area of the isoceles triangle
DiKsa [7]

Answer:

This is a long answer. I got 82.5

Step-by-step explanation:

Area of isoceles triangle is

\frac{1}{2} (b)(h)

where b is the base and h is height.

Let draw a altuide going through Point D that split side FE into 2 equal lines. Let call that point that is equidistant from FE, H.

Since it is a altitude,it forms a right angle. So angle H=90.

Angle H is equidistant from F and E so

FH=11

EH=11.

The height is still unknown.

We can use pythagorean theorem to find side h but we need to know the slanted side or side DF to use the theorem.

Using triangle DFH, we know that angle H is 90 and angle F is 34. So using triangle interior rule,Angle D equal 56.

  • We know side FH=11
  • We know Angle D equal 56
  • We are trying to find side DF
  • We know angle H equal 90

We can use law of sines to find side DF

\frac{fh}{ \sin(d) }  =  \frac{df}{ \sin(h) }

Plug in the numbers

\frac{11}{ \sin(56) } =  \frac{df}{ \sin(90) }

sin of 90 =1 so

\frac{11}{ \sin(56) }  = df

Side df is about 13.3 inches.

Since we know our slanted side is 13.3 we can set up our pythagorean theorem equation,

(fh) {}^{2}  + (dh) {}^{2}  = df {}^{2}

(11) {}^{2}  +( dh) {}^{2}  = (13.3) {}^{2}

121 + dh {}^{2}  = 176.89

(dh) {}^{2}  = 55.89

\sqrt{55.89}  = 7.5

is approximately 7.5 so dh=7.5 approximately.

Now using base times height times 1/2 multiply them out

\frac{1}{2} (22)(7.5)

82.5

8 0
3 years ago
Need help on this question
faust18 [17]

Answer:

Step-by-step explanation:

5 units

8 0
3 years ago
Paul has three cube-shaped boxes. Each box is a different size
qwelly [4]

Answer:

See explanation

Step-by-step explanation:

Paul has three cube-shaped boxes. Each box is a different size and they are stacked from the largest to the smallest. Some information about the boxes is given below.

  • The combined volume of the three boxes is 1,197 cubic inches.
  • The area of one face of the medium box is 49 square inches.
  • The volume of the smallest box is 218 cubic inches less than the volume of the medium box.

1. The medium box has the area of one face of 49 square inches, then

a^2=49\\ \\a=7\ inches

is the side length.

The volume of the medium box is

a^3=7^3=343\ in^3.

2. The volume of the smallest box is 218 cubic inches less than the volume of the medium box, then the volume of the smallest box is

343-218=125\ in^3.

Ib is the side length, then

b^3=125\\ \\b=5\ inches

The area of one face is

b^2=5^2=25\ in^2.

3. The volume of the largest box is

1,197-343-125=729\ in^3,

then if c is the side length,

c^3=729\\ \\c=9\ inches.

4. The total height of the stack is the sum of all sides lengths:

a+b+c=7+5+9=21\ inches

5. Find the surface area of each box:

  • small 6b^2=6\cdot 5^2=6\cdot 25=150\ in^2;
  • medium 6a^2=6\cdot 7^2=6\cdot 49=294\ in^2;
  • large 6c^2=6\cdot 9^2=6\cdot 81=486\ in^2.

In total, Paul needs

150+294+486=930\ in^2

of wrapping paper. He has 1,000 square inches, so Paul has enough paper to wrap all 3 boxes.

8 0
4 years ago
Please help me asap!!!
Dmitry [639]

Answer:

So here is how we are going to get the measure of angle 2.

Since given that angle COE measures 55°, we will equate m∠2 = 2x and m∠3 = x+10 with 55. So, 55 = 2x + x + 10

55 = 3x + 10

55-10 = 3x

45 = 3x << divide both sides by 3 and the result is

15 = x

So now that we know x, we can now solve for angle 2.

m∠2 = 2x

m∠2 = 2(15)

m∠2 = 30°

I hope that this is the answer that you are looking for.

5 0
3 years ago
M=⅗ and y intercept is -6
ladessa [460]

Answer:

y=\frac{3}{5}x-6

Step-by-step explanation:

Remember the slope-intercerpt form

y=mx+b

4 0
3 years ago
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