Is this statement true? (x/y)-z=x/(y-z)
1 answer:
You might be interested in
Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
<h2>Steps</h2>
So firstly, we need to find the discounted price. Since this is going to be a <em>decrease by percentage</em>, we will be using this format:
- (1 - p)m
- <em>(p = percentage in decimal form and m = original price)</em>
In this case:
Now that we have the discounted price, we must apply the 4.5% sales tax. Since this is going to be an <em>increase by percentage</em>, we will be using this format:
- (1 + p)m
In this case:
Now we have the discounted price with the sales tax. Now all we have to do is add the shipping fee:
<u>The total price of Enzel's purchase is $80.07.</u>