All categories

3 years ago

Liam walks 2 kilometers every day. How far does Liam walk in 7 days?

Mathematics

2 answers:

sweet [91]3 years ago

5 0

Answer: 14 KILOMETERS IN 7 DAYS.

Step-by-step explanation:

2 kilometers = each day

7 days= weeks

2x7= 14 kilometers in 7 days.

PLEASE GIVE THANKS AND GOOD RATING AND ALL THAT STUFF

gavmur [86]3 years ago

4 0

Answer:

it's either 14 or 9

Step-by-step explanation:

2 x 7 = 14

2+7=9

or 2+5=7

You might be interested in

Help please and simplify answer in radical form if needed

deff fn [24]

Answer:

$16\sqrt{3}\:\mathrm{units^2}$

Step-by-step explanation:

The area of an equilateral triangle with side length $s$ is equal to $\frac{\sqrt{3}}{4}s^2$ . Since the perimeter is 24 units and there are three equal sides to an equilateral triangle, each side is $24\div 3=8$ units.

Substituting in this value, we get:

$\frac{\sqrt{3}}{4}8^2=\frac{64\sqrt{3}}{4}=\boxed{16\sqrt{3}}$

6 0

3 years ago

Factor the expression completely.<br> 18X2-8

Tcecarenko [31]

18x=2-8

18x=-6

x=-3

that would be my answer if not then ask someone else

3 0

3 years ago

Read 2 more answers

Please help im very confused

joja [24]

Download the app photo math, it will give u all the answers for those and shows the work

7 0

3 years ago

"find the cost per ounce of a sunscreen made from 140 oz of lotion that cost $3.45 per ounce and 90 oz of lotion that cost $14.0

Olegator [25]

Sunscreen approx. 40.6 cents an oz
Lotion 6.4 cents an oz

5 0

3 years ago

Point B has coordinates (4,1). The x-coordinate of point A is -4. The distance between point A and point B is 10 units. What a

klasskru [66]

Given:

Point B has coordinates (4,1).

The x-coordinate of point A is -4.

The distance between point A and point B is 10 units.

To find:

The possible coordinates of point A.

Solution:

Let the y-coordinate of point A be y. Then the two points are A(-4,y) and B(4,1).

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The distance between point A and point B is 10 units.

$\sqrt{(4-(-4))^2+(1-y)^2}=10$

Taking square on both sides, we get

$(8)^2+(1-y)^2=100$

$(1-y)^2=100-64$

$(1-y)^2=36$

Taking square root on both sides, we get

$(1-y)=\pm \sqrt{36}$

$-y=\pm 6-1$

$y=1\mp 6$

$y=1-6$ and $y=1+6$

$y=-5$ and $y=7$

Therefore, the possible coordinates of point A are either (-4,-5) or (-4,7).

7 0

2 years ago