Answer:
Since there is one value of y for every value of x in (−4,8),(−2,4),(0,1),(2,4), ( 4,8), this relation is a function. The relation is a function.
DIFFERENTIATION
6+f(28+b(4)=6+112f+4bf
b=6+112f/-4f
b=1*6^0+1*112f^0/1*-4f^0
b=1+1/1
b=2
Answer:
3(6) -1
------------
2(6)+1
Step-by-step explanation:
first find r(6)
r(6) =3(6) -1
= 18 -1
Then find s(6)
s(6) = 2(6)+1
Then divide
r(6)/s(6) = 3(6) -1
------------
2(6)+1
For this case we have the following expression:
By definition, a coefficient is the term that accompanies one or more variables.
For example:
The coefficient of the linear term is 3.
So, in the given expression we have to:
-4 is the term that accompanies the variables xy.
Answer:
-4
Answer:
The next step is to find the point on the circle which makes a tangent line that passes through the outside point.
Step-by-step explanation:
A tangent line to a circle is a line that touches the circle at exactly one point. You need two points to draw a line. You already have one point and the circle, then you need the other point, which lies on the circle. These two points have to lie on the same line. Notice that there are two possible tangent lines.
