Answer:
Elephant and the eath because Fg is determined by Mass of an object.. So elephant has greater mass therefore, it's Fg is higher
A simple electric has two terminals i.e. negative and positive, And it has a top and a bottom namely Metal Cap and Metal disc.
<h3><u>Description of each part :-</u></h3>
- <u>Metal</u><u> </u><u>cap</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>part</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>above</em><em> </em><em>the</em><em> </em><em>positive</em><em> </em><em>terminal</em><em>,</em><em> </em><em>a</em><em> </em><em>cap</em><em> </em><em>of</em><em> </em><em>metal</em><em> </em><em>through</em><em> </em><em>which</em><em> </em><em>the</em><em> </em><em>positively</em><em> </em><em>charged</em><em> </em><em>electrons</em><em> </em><em>are</em><em> </em><em>passed</em><em>.</em>
- <u>Metal</u><u> </u><u>disc</u><u>:</u><u>-</u><u> </u><em>The part which is </em><em>below</em><em> the </em><em>negative</em><em> terminal, a </em><em>disc</em><em> of metal through which the </em><em>negatively</em><em> </em><em>charged</em><em> electrons are passed.</em>
- <u>Positive</u><u> </u><u>terminal</u><u>:</u><u>-</u><u> </u><em>In</em><em> </em><em>a</em><em> </em><em>circuit</em><em> </em><em>the</em><em> </em><em>current</em><em> </em><em>flows</em><em> </em><em>from</em><em> </em><em>positive</em><em> </em><em>terminal</em><em> </em><em>to</em><em> </em><em>negative</em><em> </em><em>terminal</em><em>.</em><em> </em>
- These terminals are also known as cathode and anode.
- Cathode is the other name for positive terminal and anode is the other name for negative terminal.
The variable represented by that symbol is: d. Net force.
Answer: (A) 1.5 m
Explanation:
This situation is due to Refraction, a phenomenon in which a wave (the light in this case) bends or changes its direction when passing through a medium with an index of refraction different from the other medium.
In this context, the index of refraction is a number that describes how fast light propagates through a medium or material.
In addition, we have the following equation that states a relationship between the apparent depth and the actual depth :
(1)
Where:
is the air's index of refraction
water's index of refraction.
is the actual depth of water
Now. when is smaller than the apparent depth is smaller than the actual depth. And, when is greater than the apparent depth is greater than the actual depth.
Let's prove it:
(2)
Finally we find the apparent depth of water, which is smaller than the actual depth: