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katovenus [111]
3 years ago
9

How much energy is required to increase the temperature of

Physics
1 answer:
Basile [38]3 years ago
6 0

Explanation:

Q=msdt

= 2 x 128 x (7-4)

=256 x 3

= 768 J

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What is physical change ?​
ss7ja [257]

Answer:

A physical change is a change to the physical—as opposed to chemical—properties of a substance. They are usually reversible. The physical properties of a substance include such characteristics as shape (volume and size), color, texture, flexibility, density, and mass.

3 0
3 years ago
Which of the following is the correct description of momentum?
victus00 [196]

Answer:

The product of mass and velocity is the correct answer

Explanation:

Momentum is defined as mass × velocity

p = mv

7 0
3 years ago
A hockey puck with a mass of 0.159 kg slides over the ice. The puck initially slides with a speed of 4.75 m/s, but it comes to a
Anton [14]

Answer:

The energy dissipated as the puck slides over the rough patch is 1.355 J

Explanation:

Given;

mass of the hockey puck, m = 0.159 kg

initial speed of the puck, u = 4.75 m/s

final speed of the puck, v = 2.35 m/s

The energy dissipated as the puck slides over the rough patch is given by;

ΔE = ¹/₂m(v² - u²)

ΔE = ¹/₂ x 0.159 (2.35² - 4.75²)

ΔE = -1.355 J

the lost energy is 1.355 J

Therefore, the energy dissipated as the puck slides over the rough patch is 1.355 J

5 0
3 years ago
Suppose you pour water into a container until it reaches a depth of 21 cm. next, you carefully pour in a 11-cm thickness of oliv
ipn [44]
<span>3040. Pascals. The density of olive oil is 0.911 g/cm^3 and the density of water is 1.000 g/cm^3. To calculate the pressure of 1 cm of water, 1000 kg/m^3 * 9.8 m/s^2 * 0.01 m = 98.000 Pa To calculate the pressure of 1 cm of olive oil 911 kg/m^3 * 9.8 m/s^2 * 0.01 m = 89.278 Pa Now to calculate the pressure at the bottom of the container, simply add the products of how many cm of each fluid you have. So 21 * 98.000 Pa + 11 * 89.278 Pa = 2058 Pa + 982.058 Pa = 3040.058 Pa So the pressure at the bottom of the container will be 3040. Pascals.</span>
8 0
3 years ago
The total consumption of electrical energy in the United States is about 1.0 1019 joules per year.
dexar [7]

Answer:

a) 316880878140.2895 Joules

b) 1056.26 Joules

c) 372.80103310622 km²

Explanation:

Energy consumption

E=\frac{P}{t}\\\Rightarrow E=\frac{1\times 10^{19}}{365.25\times 24\times 60\times 60}\\\Rightarrow E=316880878140.2895\ W

Average rate of electrical energy consumption is 316880878140.2895 Joules

Total population = 300 million

E=\frac{316880878140.2895}{300\times 10^6}\\\Rightarrow E=1056.26\ J

Each person consumes 1056.26 Joules.

Efficiency = 0.85

Power from Sun

0.85\times 1000=850\ W/m^2

Area

\frac{316880878140.2895}{850}=372801033.10622\ m^2

Converting to km²

372801033.10622=\frac{372801033.10622}{1000\times 1000}=372.80103310622\ km^2

Area required to collect the electrical energy used in the United States is 372.80103310622 km²

4 0
3 years ago
Read 2 more answers
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