Answer:
F=124.03 N
Explanation:
Given data
mass m=5.00 kg
y(t)=(2.80 m/s)t+(0.61m/s³)t³
To find
Force F at t=4.10 s
Solution
As
![y(t)=(2.80m/s)t+(0.61m/s^{3} )t^{3}](https://tex.z-dn.net/?f=y%28t%29%3D%282.80m%2Fs%29t%2B%280.61m%2Fs%5E%7B3%7D%20%29t%5E%7B3%7D)
derivative with respect to time we get
![\frac{dy(t)}{dt} =v(t)=2.80+1.83t^{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%28t%29%7D%7Bdt%7D%20%3Dv%28t%29%3D2.80%2B1.83t%5E%7B2%7D)
again derivative with respect to time to get acceleration
![\frac{dv(t)}{dt}=a(t)=3.66t](https://tex.z-dn.net/?f=%5Cfrac%7Bdv%28t%29%7D%7Bdt%7D%3Da%28t%29%3D3.66t)
at t=4.10 s then a(t) is
a=3.66(4.10)
a=15.006 m/s²
Now to use Newton law to find force in y direction
![F-mg=ma\\F=mg+ma\\F=(5.00kg)(9.8m/s^{2} )+(5.00kg)(15.006m/s^{2} )\\F=49N+75.03N\\F=124.03N](https://tex.z-dn.net/?f=F-mg%3Dma%5C%5CF%3Dmg%2Bma%5C%5CF%3D%285.00kg%29%289.8m%2Fs%5E%7B2%7D%20%29%2B%285.00kg%29%2815.006m%2Fs%5E%7B2%7D%20%29%5C%5CF%3D49N%2B75.03N%5C%5CF%3D124.03N)
Answer:
2.1m/s towards your grandmother's house
Explanation:
Given parameters:
Time taken = 204s
Distance = 430m
Unknown:
Velocity = ?
Solution:
The velocity is determined by:
Velocity =
Velocity =
= 2.1m/s towards your grandmother's house
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