Answer:
A) speed = 3144287.425 m/s
B) period = 8.57x10^-8 s
C) KE = 3.302x10^-14 J
D) potential difference = 103187.5 V
Explanation:
Detailed explanation and calculation is shown in the image below.
Answer:
Angle turn pulley is 113 rad
Explanation:
given data
angular speed w = 12.5 rad/s
angular acceleration a 3.41 rad/s²
time t = 5.26 s
to find out
what angle does the pulley turn
solution
we get here angle by this equation that is here
angle turn = w × t + 0.5 × a × t² ......................1
put here value we get
angle turn = w × t + 0.5 × a × t²
angle turn = 12.5 × 5.26 + 0.5 × 3.41 × 5.26²
Angle turn = 65.75 + 47.17
Angle turn = 112.92 rad = 113 rad
Answer:
-39.2m/s
Explanation:
Using the equation of motion;
v = u + at
Since the ball is thrown upward, the acceleration due to gravity acting on it will be negative, hence a = -g
v = u - gt
Since g = 9.8m/s²
t = 4.0s
u = 0m/s
v = 0 + (-9.8)(4)
v = 0 + (-9.8)(4)
v = -39.2m/s
Hence the speed of the ball before release is -39.2m/s
Answer:
The final kinetic energy of the Helium nucleus (alpha particle) after been scattered through an angle of 120° is
8.00 x 10-13J
Explanation:
In Rutherford Scattering experiment, the collision of the helium nucleus with the gold nucleus is an ELASTIC COLLISION. This means that the kinetic energy is conserved ( The same before and after the collision).
Thus, the final kinetic energy of the helium nucleus is the same as initial kinetic energy (8.00 x 10^-13Joules)
Although, the kinetic energy is converted to potential energy in Coulomb's law equation.
That is,
1/2(mv^2) = (K* q1q2)/r
Where m is the mass of helium nucleus, v is its colliding velocity, k is electrostatic constant, q1 is the charge on helium nucleus, q2 is the charge on gold nucleus, r is impact parameter
Answer:
Heat is transfered via solid material (conduction), liquids and gases (convection), and electromagnetical waves (radiation).
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