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erica [24]
3 years ago
7

We divide the electromagnetic spectrum into six major categories of light, listed below. Rank these forms of light from left to

right in order of increasing wavelength. To rank items as equivalent, overlap them.A) radio waves,B) infrared,C) visible light,D) ultraviolet,E) X-rays,F) gamma rays.
Physics
1 answer:
algol133 years ago
6 0

Answer:

gamma rays  < X-ray  < ultraviolet ray < visible light < infrared  < radio wave

Explanation:

given light form,

A) radio waves,B) infrared,C) visible light,D) ultraviolet,E) X-rays,F) gamma rays

we know,

wavelength of radio wave = 10000 Km

wavelength of infrared = 700 nanometers (nm) to 1 millimeter (mm)

wavelength of visible light = 380 to 740 nm

wavelength of ultraviolet ray = 10 nm to 400 nm

wavelength of X-ray =  0.01 to 10 nm

wavelength of gamma rays = 100 picometer

so, the order of rays.

gamma rays  < X-ray  < ultraviolet ray < visible light < infrared  < radio wave

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An organ pipe open at both ends has two successive harmonics with frequencies of 220 Hz and 240 Hz. What is the length of the pi
Harman [31]

Answer:

The  length is  l  =  8.6 \  m

Explanation:

From the question we are told that

   The frequencies of the two successive harmonics are f_1 =  220 \ Hz ,  f_2  =  240 \  Hz

   The speed of sound in the air is  v_s  =  343 \  m/s

Generally the frequency of a given harmonic is mathematically represented as

     f_n  =  \frac{n  v  }{2l}

Here  n defines  the position of the harmonics

Now since the position of both harmonic is not know but we know that they successive then we can represented them mathematically as

    220  =  \frac{n v}{2l}

and  

     240  =  \frac{(n+1) v}{2l}

So

   \frac{(n + 1 ) v}{2l} - \frac{n v}{2l}  =  240-220

=>  \frac{v}{2l}  =  20

=>   l  =  8.6 \  m

7 0
3 years ago
A spring stretches by 0.0208 m when a 3.39-kg object is suspended from its end. How much mass should be attached to this spring
sashaice [31]

Answer:

COMPLETE QUESTION

A spring stretches by 0.018 m when a 2.8-kg object is suspended from its end. How much mass should be attached to this spring so that its frequency of vibration is f = 3.0 Hz?

Explanation:

Given that,

Extension of spring

x = 0.0208m

Mass attached m = 3.39kg

Additional mass to have a frequency f

Let the additional mass be m

Using Hooke's law

F= kx

Where F = W = mg = 3.39 ×9.81

F = 33.26N

Then,

F = kx

k = F/x

k = 33.26/0.0208

k = 1598.84 N/m

The frequency is given as

f = ½π√k/m

Make m subject of formula

f² = ¼π² •(k/m

4π²f² = k/m

Then, m4π²f² = k

So, m = k/(4π²f²)

So, this is the general formula,

Then let use the frequency above

f = 3Hz

m = 1598.84/(4×π²×3²)

m = 4.5 kg

4 0
3 years ago
Because so little can be found of the first rocks to form on
fgiga [73]

Answer:

B is the answer

Explanation:

0-/-<

7 0
3 years ago
(Physical Science) What is the wavelength of light waves if their frequency is 5.0 x 10^14 Hz and the speed of light is 3 x 10^8
MaRussiya [10]

Explanation:

Wavelength = speed of light/frequency

Answer is

6 \times  {10}^{ - 7}

4 0
2 years ago
Which region of a longitudinal wave is this?
ipn [44]
I think the correct answer is is D.
8 0
3 years ago
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