Answer:
1)-
How to solve your question
Your question is
4(4−72)−9(5+2)
4(4y-7y^{2})-9(5y+2)4(4y−7y2)−9(5y+2)
Simplify
1
Rearrange terms
4(4−72)−9(5+2)
4({\color{#c92786}{4y-7y^{2}}})-9(5y+2)4(4y−7y2)−9(5y+2)
4(−72+4)−9(5+2)
4({\color{#c92786}{-7y^{2}+4y}})-9(5y+2)4(−7y2+4y)−9(5y+2)
2
Distribute
4(−72+4)−9(5+2)
{\color{#c92786}{4(-7y^{2}+4y)}}-9(5y+2)4(−7y2+4y)−9(5y+2)
−282+16−9(5+2)
{\color{#c92786}{-28y^{2}+16y}}-9(5y+2)−28y2+16y−9(5y+2)
3
Distribute
−282+16−9(5+2)
-28y^{2}+16y{\color{#c92786}{-9(5y+2)}}−28y2+16y−9(5y+2)
−282+16−45−18
-28y^{2}+16y{\color{#c92786}{-45y-18}}−28y2+16y−45y−18
4
Combine like terms
2)
−17y+17z+24
See steps
Step by Step Solution:

STEP1:Equation at the end of step 1
((24 - 4 • (5y - 6z)) + 3y) - 7z
STEP2:
Final result :
-17y + 17z + 24
−282+16−45−18
-28y^{2}+{\color{#c92786}{16y}}{\color{#c92786}{-45y}}-18−28y2+16y−45y−18
−282−29−18
-28y^{2}{\color{#c92786}{-29y}}-18−28y2−29y−18
Solution
−282−29−18
Answer:
1/3
Step-by-step explanation:
The period required to pay for the car is not given. However let us assume this interest rate of 6.5% is per annum, on simple interest terms.
I= PRT
where I is the interest accrued, P is the principal, R is the rate and T is the time.
If the car is paid for in one year then the final cost will be:
I = 29990 × 6.5% × 1
6.5% must be expressed as a decimal fraction so we divide by 100 to get 0.065
I= 29990 × 0.065 × 1
I = 1,949.35
29990 + 1949.35 = 31939.35 dollars.
If the car is paid for in five years on simple interest terms then the final cost will be :
I = 29990 × 0.065 ×5 = 9,746.75
29990 + 9.746.75 = 39,736.75 dollars
The answer is 11/18 = 0.6111
Answer:
Standard form
Step-by-step explanation:
