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3 years ago

How do I solve this question I’ve been stuck on this since last night

Mathematics

1 answer:

meriva3 years ago

8 0

Observation one

From the markings on the diagram <1 = 60o The left triangle is at least isosceles. Therefore equal sides produce equal angles opposite them.

Now we have accounted for 2 angles that are equal (each is 60 degrees) and add up to 120 degrees. The third angle (angle 2) is found from this equation.

<1 + 60 + <2 = 180 degrees. All triangles have 180 degrees.

60 + 60 + <2 = 180

Observation 2

<2 = 60 degrees.

120 + <2 = 180

m<2 = 180 - 120

m<2 = 60 degrees.

Observation 3

m<3 = 120

<2 and <3 are supplementary.

Any 2 angles on the same straight line are supplementary

60 + <3 = 180

<3 = 180 - 60

<3 = 120

Observation 4

m<4 = 40 degrees.

All triangles have 180 degrees. No exceptions.

m<4 + 20 +m<3 = 180

m<4 + 20 + 120 = 180

m<4 + 140 = 180

m<4 = 180 - 140

m<4 = 40

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Write the equation of the ellipse using the given information:

horsena [70]

We know, equation of ellipse is given by :

$\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1$

Here,

(h,k) is centre of the ellipse = (0,0).

a = major axis = 8.

b = minor axis = 4.

Putting all given value in above equation, we get :

$\dfrac{(x-0)^2}{8^2}+\dfrac{(y-0)^2}{4^2}=1\\\\\dfrac{x^2}{8^2}+\dfrac{y^2}{4^2}=1\\\\\dfrac{x^2}{64}+\dfrac{y^2}{16}=1$

Hence, this is the required solution.

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3 years ago

What’s 836 written in expanded form

kotegsom [21]

8.36x10^3 ? i think :(. i'm not sureeee

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3 years ago

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Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C

netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:

 $|PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}$

Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.

$|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5$

$|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6$

$|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4$

$|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \ \sqrt{25}=5$

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3 0

3 years ago

Using the image above, if the density of the LEGO piece is 0.85 g/cm^3, what COULD be a possible measurement for the density of

grin007 [14]

The Lego is submerged under the oil and therefore, is more dense than the oil

The possible density of the oil is the option;

0.79 g/cm³

Reason:

Given:

The density of Lego = 0.85 g/cm³

Density of oil = Required

Solution:

The density of an object is the mass per unit volume it occupies

$Density = \dfrac{Mass}{Volume}$

Increase in density increases the mass a unit volume occupies, therefore, a

more dense object is heavier than a less dense object such that the less

dense object will float on a dense object

The oil is floating on the Lego, therefore, the Lego is more dense than the

oil, and we have;

Density of Lego > Density of oil

The density of Lego = 0.85 g/cm³

Therefore;

0.85 g/cm³ > Density of oil

From the given options, the option that has a density less than 0.85 g/cm³ is the the option 0.79 g/cm³

Therefore, the possible density of the oil is 0.79 g/cm³

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2 years ago

I need help please to find the answer

Katena32 [7]

B! If you draw the line of symmetry diagonally, you have two triangles

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