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butalik [34]
2 years ago
7

HELP HOW DO I GET MORE THAN ONE PICTURE WHEN I ASK A QUESTION ‍♀️‍♀️

Mathematics
1 answer:
Andrew [12]2 years ago
4 0

Answer:

Press browse files after the 1st one

Step-by-step explanation:

That just look at circle

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Hellllllllllllllllllllllllllp me plsssssssssssssssssssssssss
Marina CMI [18]

first one: 1 1/2 pints

second: 44 months

3 0
3 years ago
Sherman has 3 cats and 2 dogs. he wants to buy a toy for each of his pets. Sherman has 22$ to spend on pet toys. How much can he
WARRIOR [948]

Sherman wants to spend on each pet, so we are assuming he wants to spend the same amount. He has 5 pets in all (3 cats, 2 dogs)

Divide 22 with 5

22/5 = 4.4

He can spend $4.40, or in fraction form:

4 4/10 (Mixed fraction)

hope this helps

6 0
3 years ago
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
Sheila bought several bags of balloons and boxes of candles. The candles cost $15 per bix, and the balloons cowt $8 per bag. She
snow_tiger [21]

Answer:

balloons= 9

candles= 8

Step-by-step explanation:

let the number of balloons be x

and candles be y

So

15x+8y=192----------1

x+y=17--------------2

from 2, x= 17-y

put x= 17-y in 1

15( 17-y)+8y=192

255-15y+8y=192

solve for y

-7y=192-255

-7y=-63

x=63/7

x=9

put x= 9 in 1

9+y=17

y= 17-9

y=8.

7 0
3 years ago
5 times 3 and 5 over 8 times 9 and 1 over 4
Ber [7]
The answer should be:
20.875

Hope this helps. 

3 0
3 years ago
Read 2 more answers
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