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butalik [34]
2 years ago
7

HELP HOW DO I GET MORE THAN ONE PICTURE WHEN I ASK A QUESTION ‍♀️‍♀️

Mathematics
1 answer:
Andrew [12]2 years ago
4 0

Answer:

Press browse files after the 1st one

Step-by-step explanation:

That just look at circle

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The image of the point (6, -9) under a translation is (11,-4). Find the coordinates
yaroslaw [1]

Answer:

( - 6 , - 1 )

Step-by-step explanation:

Let's find the rule of that transformation:

1 +  = 4 ⇒  = 3

9 +  = 10 ⇒  = 1

Thus, the rule of given transformation is ( x + 3 , y + 1 )

So, the image of the point ( - 9 , - 2 ) is

( - 9 + 3 , - 2 + 1 ) = ( - 6 , - 1 )

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svetoff [14.1K]

Answer:

lol you've asked like 10 probability questions in 20 minutes i wonder what chapter you're studying

Step-by-step explanation:

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kodGreya [7K]

Answer:

9. 16.34

10. 51.84

11. 20.11

12. 76.03

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just look up circumference of a circle and you should be able to put the radius in the first thing that pops up :)

4 0
2 years ago
198.9 grams equals how many ounces?
Rudiy27

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5 0
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Suppose the total area is represented by the equation x^2+14x+24. If the area 1 is x^2 square units and area IV is 24 units, wha
Nutka1998 [239]

Answer:

See Explanation

Step-by-step explanation:

Given

Total = x^2 + 14x + 24

Area\ I = x^2

Area\ IV = 24

Required

True about area II and III

The question is incomplete; so, I will answer using general knowledge.

If the total area is:

Total = x^2 + 14x + 24

And there are 4 areas, then;

Total = Area\ I + Area\ II + Area\ III + Area\ IV

Rewrite as:

Total = Area\ I + Area\ IV+ Area\ II + Area\ III

This gives:

x^2 + 14x + 24 = x^2 + 24+ Area\ II + Area\ III

Collect like terms

x^2 -x^2 + 14x + 24 -24=  Area\ II + Area\ III

14x =  Area\ II + Area\ III

Rewrite as:

Area\ II + Area\ III  = 14x

<em>So, the sum of areas III and IV must be 14x</em>

4 0
3 years ago
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