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3 years ago

If a 0.500-kilogram pair of running shoes would weigh 11.55 newtons on Jupiter, what is the strength of gravity there?

1 answer:

Taya2010 [7]3 years ago

6 0

Weight is the object's mass times the force of gravity acting upon it. If a .5 kg object weighs 11.5 N on Jupiter, it's acceleration of gravity would be 11.5/.5 which is 23 meters per second squared.

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Rena is suffering from high fever since night. her aunt measures her body temp to 39 degree using a Celsius thermometer. but she

Usimov [2.4K]

Answer:

102.2 degrees Fahrenheit

Explanation:

You can use this formula in order to convert from Celsius to Fahrenheit:

(C x 9/5) +32

39 x 9 = 351

351 / 5 = 70.2

70.2 + 32 = 102.2

4 0

3 years ago

Read 2 more answers

Seberkas cahaya monokromatik dijatuhkan pada kisi difraksi dengan 5000 goresan/cm menghasilkan spectrum garis terang orde kedua

Vlada [557]

Answer:

500 nm

Explanation:

In this problem, we have a diffraction pattern created by light passing through a diffraction grating.

The formula to find a maximum in the pattern produced by a diffraction grating is the following:

$d sin \theta = m\lambda$

where:

d is the distance between the lines in the grating

$\theta$ is the angle at which the maximum is located

m is the order of the maximum

$\lambda$ is the wavelength of the light used

In this problem we have:

$\theta=30^{\circ}$ is the angle at which is located the 2nd-order bright line, which is the 2nd maximum

n = 5000 lines/cm is the number of lines per centimetre, so the distance between two lines is

$d=\frac{1}{d}=\frac{1}{5000}=2\cdot 10^{-4} cm = 2\cdot 10^{-6} m$

Re-arranging the equation for $\lambda$ , we find the wavelength of the light used:

$\lambda=\frac{d sin \theta}{m}=\frac{(2\cdot 10^{-6})(sin 30^{\circ})}{2}=5\cdot 10^{-7} m = 500 nm$

4 0

3 years ago

Is the mechanical form of power different from the electrical form?

Artemon [7]

Yes there is a difference.

8 0

3 years ago

Most of the Earth's volcanoes occuWhen fossils or minerals form, certain unstable elements are sometimes locked into them. The p

Anna007 [38]

Radioactive dating, is your answer.

4 0

3 years ago

5. A 4.00 kg object slides down a frictionless inclined plane with an acceleration of 3.00 m/s2. What is the angle of the inclin

Kazeer [188]

Answer:

The angle of the incline above horizontal is 17.81 degrees.

Explanation:

Given that,

Mass of the object, m = 4 kg

Acceleration of the object above the incline, $a=3\ m/s^2$

We need to find the angle of the incline above horizontal. The net force acting on the object along the incline is given by :

$F_{net}=mg\ sin\theta$

$ma=mg\ sin\theta$

$a=g\ sin\theta$

$sin\theta=\dfrac{a}{g}$

$sin\theta=\dfrac{3}{9.8}$

$\theta=17.81^{\circ}$

So, the angle of the incline above horizontal is 17.81 degrees. Hence, this is the required solution.

5 0

4 years ago