Answer
given,
wavelength = λ = 18.7 cm
= 0.187 m
amplitude , A = 2.34 cm
v = 0.38 m/s
A) angular frequency = ?
angular frequency ,
ω = 2π f
ω = 2π x 2.03
ω = 12.75 rad/s
B) the wave number ,
C)
as the wave is propagating in -x direction, the sign is positive between x and t
y ( x ,t) = A sin(k x - ω t)
y ( x ,t) = 2.34 x sin(33.59 x - 12.75 t)
the <u>average powe</u><u>r</u> output of the sun is <u>3.8 × </u>
<u> W</u> given that about 1350 w/m2 reaches the upper atmosphere of the earth.
As we know intensity falling over a surface is equal to Energy falling per unit area per unit volume.
I = 
Since Power is equal to energy/time
I = power/area
or
Power = Intensity × area
Now, Distance from Sun to Earth , r = 149.6 ×
m
So, Surface area of the sphere of radius is:
A = 4 π 
= 4 × 3.14 × (149.6 ×
)²
= 2.81 ×
m²
Thus Average Power output of the sun will be:
P = 1350 × 2.81 × 
= 3.7935 × 
P = 3.8 ×
W
So the average power output of the sun is 3.8 ×
W.
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Answer:
The Statement is wrong because the reverse is the case as it is the kinetic energy that is being transformed to gravitational potential energy.
Explanation:
As your friend throws the baseball into the air the ball gains an initial velocity (u) and this makes the Kinetic energy to be equal to

Here m is the mass of the baseball
Now as this ball moves further upward the that velocity it gained reduce due to the gravitational force and this in turn reduces the kinetic energy of the ball and this kinetic energy lost is being converted to gravitational potential energy which is mathematically represented as (m×g×h)
as energy can not be destroyed but converted to a different form according to the first law of thermodynamics
Looking a the formula for gravitational potential energy we see that the higher the ball goes the grater the gravitational potential energy.
Changes in the earths ability to reflect sunlight (called the 'albeido') due to clouds and other weather like ice formations set up feedback loops that prevent a perfect equlibrium with the sun.