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bearhunter [10]
3 years ago
12

A projectile is fired at an angle such that the vertical component of its velocity

Physics
1 answer:
mestny [16]3 years ago
3 0

Answer:

<em>It takes 3 seconds to reach its high point</em>

Explanation:

<u>Projectile Motion</u>

In a projectile motion (or 2D motion), the object is launched with an initial angle θ and an initial velocity vo.

The components of the velocity are

v_{ox}=v_o\cos\theta

v_{oy}=v_o\sin\theta

The speed in the horizontal direction at any time t is:

v_y=v_o\sin\theta-g.t

The time taken to reach the maximum height is when vy=0, or:

\displaystyle t_m=\frac{v_o\sin\theta}{g}

We are given the y-component of the velocity, thus:

\displaystyle t_m=\frac{30~m/s}{10~m/s^2}

t_m=3~s

It takes 3 seconds to reach its high point

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A steady beam of alpha particles (q = + 2e, mass m = 6.68 × 10-27 kg) traveling with constant kinetic energy 22 MeV carries a cu
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Explanation:

q = 2e = 3.2 x 10^-19 C

mass, m = 6.68 x 10^-27 kg

Kinetic energy, K = 22 MeV

Current, i = 0.27 micro Ampere = 0.27 x 10^-6 A

(a) time, t = 2.8 s

Let N be the alpha particles strike the surface.

N x 2e = q

N x 3.2 x 10^-19 = i t

N x 3.2 x 10^-19 = 0.27 x 10^-6 x 2.8

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(b) Length, L = 16 cm = 0.16 m

Let N be the alpha particles

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22 x 1.6 x 10^-13 = 0.5 x 6.68 x 10^-27 x v²

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v = 3.25 x 10^7 m/s

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