3 years ago

Calculate the period of oscillation of a pendulum with a small amplitude whose length is 2.5 meters.

Physics

1 answer:

UkoKoshka [18]3 years ago

4 0

Answer:

Period is 1.57 seconds

Explanation:

From simple harmonic motion :

$period = 2\pi \sqrt{ \frac{l}{g} }$

T = 2π√(2.5÷10)

T = 0.25 × 2π

T = 1.57 s

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