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4 years ago

To decrease carbon monoxide production, is added to the combustion process___.

Engineering

1 answer:

notka56 [123]4 years ago

5 0

Answer:To decrease carbon monoxide production oxygen is added to the combustion process.

Explanation: Carbon Monoxide(CO) is a type of harmful gas that is produced when there is a incomplete combustion of carbon. It is in odorless and poisonous/toxic form . Due to the less amount of oxygen there is incomplete combustion , so if there is more supply of oxygen the result will be a complete combustion and this would decrease the production of carbon monoxide.

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Neon is compressed from 100 kPa and 20◦C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and

PIT_PIT [208]

Answer:

The specific volume is reduced in 80 per cent due to isothermal compression.

Specific enthalpy remains constant.

Explanation:

Let suppose that neon behaves ideally, the equation of state for ideal gases is:

$P\cdot V = n\cdot R_{u}\cdot T$

Where:

$P$ - Pressure, measured in kilopascals.

$V$ - Volume, measured in cubic meters.

$n$ - Molar quantity, measured in kilomoles,

$T$ - Temperature, measured in kelvins.

$R_{u}$ - Ideal gas constant, measured in $\frac{kPa\cdot m^{3}}{kmol\cdot K}$ .

On the other hand, the molar quantity ( $n$ ) and specific volume ( $\nu$ ), measured in cubic meter per kilogram, are defined as:

$n = \frac{m}{M}$ and $\nu = \frac{V}{m}$

Where:

$m$ - Mass of neon, measured in kilograms.

$M$ - Molar mass of neon, measured in kilograms per kilomoles.

After replacing in the equation of state, the resulting expression is therefore simplified in term of specific volume:

$P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T$

$P\cdot \nu = \frac{R_{u}\cdot T}{M}$

Since the neon is compressed isothermally, the following relation is constructed herein:

$P_{1}\cdot \nu_{1} = P_{2}\cdot \nu_{2}$

Where:

$P_{1}$ , $P_{2}$ - Initial and final pressure, measured in kilopascals.

$\nu_{1}$ , $\nu_{2}$ - Initial and final specific volume, measured in cubic meters per kilogram.

The change in specific volume is given by the following expression:

$\frac{\nu_{2}}{\nu_{1}} = \frac{P_{1}}{P_{2}}$

Given that $P_{1} = 100\,kPa$ and $P_{2} = 500\,kPa$ , the change in specific volume is:

$\frac{\nu_{2}}{\nu_{1}} = \frac{100\,kPa}{500\,kPa}$

$\frac{\nu_{2}}{\nu_{1}} = \frac{1}{5}$

The specific volume is reduced in 80 per cent due to isothermal compression.

Under the ideal gas supposition, specific enthalpy is only function of temperature, as neon experiments an isothermal process, temperature remains constant and, hence, there is no change in specific enthalpy.

Specific enthalpy remains constant.

8 0

3 years ago

Five kg of nitrogen gas (N2) in a rigid, insulated container fitted with a paddle wheel is initially at 300 K, 150 kPa. The N2 g

andrew-mc [135]

Answer:

A) attached below

B) 743 KJ

C) 1.8983 KJ/K

Explanation:

A) Diagram of system schematic and set up states

attached below

B) Calculate the amount of work received from the paddle wheel

assuming ideal gas situation

v1 = v2 ( for a constant volume process )

work generated by paddle wheel = system internal energy

dw = mCv dT . where ; Cv = 0.743 KJ/kgk

= 5 * 0.743 * ( 500 - 300 )

= 3.715 * 200 = 743 KJ

C) calculate the amount of entropy generated ( KJ/K )

S2 - S1 = 1.8983 KJ/K

attached below is the detailed solution

4 0

3 years ago

What are the standard procedures involved in the fixing/securing of cables?

Sladkaya [172]

Cable should be pre-cut and hung suspended for 48 hours to develop its most natural set and lay prior to installation.

Cable should be installed with, not against, its natural set. ...

Strain relief on either end will reduce conductor breakage at the flex points.

4 0

2 years ago

Assume we have one road section which has 3 lanes in both directions. If the Sf for both direction is 75 mph, and Dj for both di

givi [52]

Answer:

i) 3750 veh/hr/ln

ii) 100 veh/mi/In

iii) 37.5 mph

Explanation:

number of lanes = 3

sf for both directions = 75 mph ( free mean speed )

Dj for both directions = 200 veh/mi/In

Calculate the value of S0, D0 (veh/mi/ln) and maximum Vm (veh/hr)

For either direction we will consider the total volume = 3 lanes

value of Dj = 3 lanes * 200 = 600 veh/mi/

i) value of SO

= ( Dj * sf ) / 4 = ( 600 * 75 ) / 4 = 11250 veh/hr = 3750 veh/hr/lane

ii) Value of DO

DO = Dj / 2 = 200 /2 = 100 veh/mi/In

iii) Value of Vm

= sf /2 = 75 / 2 = 37.5 mph

5 0

3 years ago

A 0.66 ft steel bar undergoes a stretch of 0.75 in in an axial direction. What is the strain? Use three significant figures (fou

Lapatulllka [165]

Answer:

The strain is 0.0947.

Explanation:

Strain is the ration of change in dimension to the original dimension under application of load. Depending upon load, the bar may stretch or compress. So, the strain can be negative in case of compression or positive in case of tension.

Step1

Given:

Original length of the steel bar is 0.66 ft or 7.92 in.

Stretch in the bar is of 0.75 in.

Calculation:

Step2

Strain is calculated as follows:

$e=\frac{\bigtriangleup l}{l_{o}}$

$e=\frac{0.75}{7.92}$

e = 0.0947

Positive sign is for stretching condition of the bar.

Thus, the strain is 0.0947.

8 0

3 years ago

To decrease carbon monoxide production______, is added to the combustion process_________.

To decrease carbon monoxide production, is added to the combustion process___.