What is a voltage divider circuit and how do you calculate the voltage across one element in a series

8. What is the density of an object with a mass of 290.5 g and volume of 83 cm 3?

Leni [432]

Answer:

The density would be 218.5

6 0

2 years ago

Carbon dioxide flows at a rate of 1.5 ft3 /s from a 3-in. pipe in which the pressure and temperature are 20 psi (gage) and 120 °

Monica [59]

Answer:

the absolute pressure in the smaller pipe = 19.63 psi

Explanation:

Let A be the diameter of the first pipe = 3 inches

Let B be the diameter of the second pipe. = 1.5 inches

To feet (ft) ; we have

Diameter of the pipe A $D_1 = (\dfrac{3}{12})ft = 0.25 \ ft$

Diameter of pipe B $D_1 = (\dfrac{1.5}{12})ft = 0.125 \ ft$

Temperature T = 120° F = (120+ 460)°R

= 580 ° R

The pressure gage to atmospheric pressure ; we have:

$P_{Absolute }=P _{Atm} + P_{guage}$

where;

atmospheric pressure = 1.47 psi

pressure gage = 20 psi

$P_{Absolute }=(1.47+20)psi$

$P_{Absolute }=34.7 \ psi$

To lb/ft²; we have:

$P_{Absolute }=(34.7 *144 ) lb/ft^2$

$P_{Absolute }=$ 4.998.6 fb/ft²

The density of carbon dioxide can be calculated by using the relation

$\rho = \dfrac{P}{RT}$

$\rho = \dfrac{4996.8}{(1130 \ lb /slug ^0 R)*(580{^0} R)}$

$\rho = 7.64*10^{-3}\ slug /ft^3$

Formula for calculating cross sectional area is

$A = \dfrac{\pi}{4}D$

For diameter of pipe $D_1 = 0.025$

A₁ = $\dfrac{\pi}{4}*0.25^2$

A₁ = 0.04909 ft²

For diameter of pipe $D_2 - 0.0125$

A₂ $=\dfrac{\pi}{4}*0.125^2$

A₂ = 0.012227 ft²

Using the continuity equation to determine the velocities V₁ and V₂ respectively.

For V₁

Q = A₁V₁

V₁ = Q₁/ A₁

V₁ = 1.5/0.04909

V₁ = 30.557 ft/s

For V₂

Q = A₂V₂

V₂= Q₂/ A₂

V₂ = 1.5/0.04909

V₂ = 30.557 ft/s

Finally; using Bernoulli's Equation to the flow of the carbon dioxide from the larger pipe to the smaller pipe ; we have:

$p_1 + \dfrac{\rho V_1^2}{2}+\gamma Z_1= p_2 + \dfrac{\rho V_2^2}{2}+\gamma Z_2$

Since the pipe is horizontal then;

$\gamma Z_1= \gamma Z_2$

So;

$p_1 + \dfrac{\rho V_1^2}{2}= p_2 + \dfrac{\rho V_2^2}{2}$

$p_2 =p_1 +\dfrac{1}{2} \rho(V_1^2-V_2^2)$

$p_2 =4996.8+\dfrac{1}{2} *7.624*10^{-3}(30.557^2-122.23^2)$

$p_2 =4943.41 \ lb/ft^2$

To psi;

$p_2 =\dfrac{4943.41 }{144}psi$

$p_2 =34.33 \ psi$ gage

The absolute pressure in the smaller pipe can be calculated as:

$p_2 _{absolute} = 34.33 - 14.7$

$p_2 _{absolute} = 19.63 \ \ absolute$

Hence, the absolute pressure in the smaller pipe = 19.63 psi

7 0

3 years ago

What is the temperature dependency of the electrical conductivity for metals and semiconductors??

geniusboy [140]

Answer and Explanation:

TEMPERATURE DEPENDENCY ON ELECTRICAL CONDUCTIVITY OF METALS : Metals are good conductors of electricity but when we increase the temperature the free electrons of metals collide with each other due to heat.There collision become very fast and so the resistance increases and so the electrical conductivity of metals decreases on increasing temperature.

TEMPERATURE DEPENDENCY ON ELECTRICAL CONDUCTIVITY OF SEMICONDUCTOR : The electrical conductivity of semiconductor is mainly sue to presence of impurities and defects as the temperature increases the impurities and defects also increases so the electrical conductivity of semiconductor increases on increasing temperature.

3 0

3 years ago

The van der Waals equation is a modification of the ideal gas equation. What two factors does this equation account for? A. (1)

Liula [17]

Answer:

E

Explanation:

The vander waals equation

$(P+n^2a/V^2)(V-nb)$ =nRT

The factor n^2a/V^2 accounts for the attractive forces between the gases molecules whereas nb accounts for the decrease in volume occupied by the gas. Therefore, correct option would be E. None of the above have BOTH of the two factors accurately stated

6 0

3 years ago

Please answer the following questions.

likoan [24]

Basically, the purposes of digital multimeter are to measure two or more electrical values such as:

principally voltage (volts)

current (Ampere)

resistance (Ohms)

8 0

3 years ago

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