What is a voltage divider circuit and how do you calculate the voltage across one element in a series

The hydrostatic force of 313920 N is acted on each wall of the swimming pool and this force is acted at 1 m from the ground. The hydrostatic force is quadruple if the height of the walls is doubled.

Explanation:

To calculate force on the walls of swimming pool whose dimensions are given as 8-m-long, 8-m-wide, and 2-m-high. We know that formula for hydrostatic force is $\text {hydrostatic force}=\text {pressure} \times \text {area,}=\rho g h \times(l \times h)$

$\equiv \rho g h^{2} l$ , we know ρ=density of fluid=1000 $g / c m^{3}$ ,

g=acceleration due to gravity=9.81 $m / s^{2}$ , h=height of the pool=2 m and l=length of the pool=8 m.

hydrostatic force on each wall= $1000 \times 9.81 \times 2^{2} \times 8$ = 313920 N.

The distance at which hydrostatic force is acted is half of the height of the swimming pool.

At 1 m from the ground this hydrostatic force is acted on each wall.

The force is quadruple if the height of the walls of the pool is doubled this is because, the height is doubled and taken as h=4 m and substitute in the equation = $\rho g h^{2} l$ = $1000 \times 9.81 \times 4^{2} \times 8$ = 1255680 N. This is 4 times 313920 N.

5 0

3 years ago

What ratio between differential gain and common-mode gain is called

dlinn [17]

Answer:

CMRR(Common Mode Rejection Ratio) is the ratio of differential gain and the common mode gain.

Explanation:

8 0

3 years ago

Calculate the impedance of a 20 mH inductor at a frequency of 100 radians/s. Calculate the impedance of a 500 µF inductor at a f

Helga [31]

Answer:

a) Zinductor = j2 Ohm

b) Zcapacitor = -j20 Ohm

c) Zseries = -j18 Ohm

d) Zparallel = -j2.22 Ohm

Explanation:

The inductor impedance is directly proportional to the frequency, therefore:

a) frequency = 100 rad/s inductor = 20mH

Zinductor = j*frequency*inductor = j*100*20*10^(-3) = j2 Ohm

b) The capacitor inductance is inversely proportional to the frequency and it's also negative, therefore:

frequency = 100 rad/s capacitor = 500 uF

Zcapacitor = j*frequency*capacitor = -j/(100*500*10^(-6)) = -j/(0.05) = -j20 Ohm

c) The equivalent impedance of these two components in series is the sum of each part, wich goes as follow:

Zseries = Zinductor + Zcapacitor = j2 -j20 = -j18 Ohm

d) The equivalent impedance of these two components in parallel is given by the following equation:

Zparallel = (Zinductor*Zcapacitor)/(Zinductor+Zcapacitor)

Zparallel = [j2*(-j20)]/(j2-j20)

Zparallel = [-40]/(-j18) = 2.22/j = -j2.22 Ohm

3 0

3 years ago

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