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Yuri [45]
4 years ago
15

A rectangle is shown. The length of the rectangle is labeled as length equal to 8 cm, and the width is labeled as width equal to

6 cm.
If each 2 cm on the scale drawing equals 4 feet, what are the actual dimensions of the room?

Length = 16 feet, width = 12 feet
Length = 10 feet, width = 8 feet
Length = 32 feet, width = 24 feet
Length = 14 feet, width = 12 feet
Mathematics
1 answer:
andrew-mc [135]4 years ago
6 0
If 2 cm = 4 feet then 1 cm = 2 feet

8 cm ⇒ 16 feet
6 cm ⇒ 12 feet

So it is 16 length and 12 width
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Answer:

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Step-by-step explanation:

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Answer:

A) There are 12 elements in the sample space.

B) The required probability is 1/4 or 0.25.

C) Yes, the events are mutually exclusive.

Step-by-step explanation:

Consider the provided information.

Part(A)

An experiment consists of first rolling a die and then tossing a coin.

Thus the sample space is:

(1,H), (2,H) (3,H) (4,H) (5,H), (6,H)

(1,T), (2,T) (3,T) (4,T) (5,T), (6,T)

Hence, there are 12 elements in the sample space.

Part(B) Let A be the event that either a 2, 3 or 4 is rolled first, followed by landing a head on the coin toss.

Now consider the above sample space. There are 3 possible case in which 2, 3 or 4 is rolled first, followed by landing a head on the coin toss.

i.e (2,H) (3,H) (4,H)

The required probability is: P(A)=\frac{3}{12}=\frac{1}{4}=0.25

Hence, the required probability is 1/4 or 0.25.

Part(C)

Mutually exclusive, means that they cannot occur at the same time.

From part (B) Event A = (2,H) (3,H) (4,H)

Let B be the event that a number less than 2 is rolled, followed by landing a head on the coin toss.

Thus, the Event B = (1,H).

Therefore, Event A and B can't be occur at the same time as P(A and B)=0.

Hence, yes, the events are mutually exclusive.

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