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Furkat [3]
3 years ago
8

HELP ME OUT PLEASE!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
galben [10]3 years ago
8 0
∠LKH corresponds to ∠FGK, as it is the angle on the line that crosses the parallel lines (an F angle).
Therefore, ∠LKH=25°
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Use the digits 2,3,and 5 to create a fraction and a whole number with a product greater than 2
mylen [45]

Product is multiplication.

Since the answer needs to be greater than 2 either the fraction needs to be an improper fraction ( meaning the fraction would be greater than 1) or the whole number would need to be greater than 2.


One answer would be 5 x 2/3 = 3 1/3

3 0
3 years ago
Solve the equation using square roots. X^2+16=0
alexgriva [62]

Answer:

<u>The answer is :</u>

<u>x₁ = 4</u>

<u>x₂ = -4</u>

Step-by-step explanation:

Let's solve the equation using square roots.

X^2+16=0

x² + 16 = 0

x² = -16 (Adding 16 at both sides of the equation)

√x² = i√16 (Square root to both sides of the equation)

x = +/- 4i (Roots of the solution)

<u>x₁ = 4i</u>

<u>x₂ = -4i</u>

5 0
3 years ago
Read 2 more answers
Value expressions-10-(-4)=
Vinvika [58]

Answer:

6

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the product? Two-thirds times eight-ninths StartFraction 10 over 27 EndFraction StartFraction 16 over 27 EndFraction Two
melomori [17]

Answer:

16/27

Step-by-step explanation:

First let's convert this info an equation and then we will solve.

(2/3) * (8/9) = ?

( 2 * 8 ) / ( 3 * 9 ) = ?

( 16 ) / ( 27 ) = ?

16 / 27 = ?

So our fractional answer is 16/27.

In words this would be sixteen over twenty seven.

Cheers.

3 0
3 years ago
Two horses are ready to return to their barn after a long workout session at the track. The horses are at coordinates H(1,10) an
lana [24]
Distance between points \left(x_1,y_1\right) and \left( x_2,y_2 \right) is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Distance from H to B:

[tex]d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269}d=\sqrt{(1-(-3))^2+(10-(-9))^2}=\sqrt{16+361}=\sqrt{376}[/tex] units.

Distance from Z to B:

d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269} units.

Horse Z is closer to the barn.

(The conversion to meters is not required; the question does not ask for actual distances, so "units" is OK.)
6 0
4 years ago
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