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Answer:
Colour | Probability
YELLOW | 0.20
WHITE | 0.18
GREEN | 0.12
RED | 0.18
BLUE | 0.32
Step-by-step explanation:
The complete question is presented on the attached image to this solution.
From the image of the spinner and the given probabilities, the combination of YELLOW, WHITE and GREEN make up exactly half of the total space on the spinner.
0.2 + 0.18 + 0.12 = 0.50
Then, BLUE and RED make up the other half of the spinner.
Probability of landing on either BLUE or RED = 1 - 0.50 = 0.50
Let P(BLUE) = x and P(RED) = y
x + y = 0.50
Two of the lines shown on the diagram are diameters of the circle.
The first line that is a diameter splits the circle into two parts; (WHITE, YELLOW, GREEN) and (RED, BLUE).
From here, we have established that x + y = 0.50
The other line that is a diameter splits The circle into two part; (WHITE, BLUE) and (YELLOW, GREEN, RED)
From this other information,
P(WHITE) + P(BLUE) = 0.50
0.18 + x = 0.50
x = 0.50 - 0.18 = 0.32
P(YELLOW) + P(GREEN) + P(RED) = 0.50
0.20 + 0.12 + y = 0.50
y = 0.50 - 0.32 = 0.18
To check, x + y = 0.32 + 0.18 = 0.50 (Correct!!)
Hope this Helps!!!
Hence, the functions that produce given sequence are:
f(n) = 2n + 1
f(n) = 2(n − 1) + 3
Further explanation:
We will put n=1,2,3,4,5 to find which functions give the given sequence
<u>f(n) = 2n − 1</u>
Putting values of n
This function doesn't generate the given sequence
<u>f(n) = 2n + 1</u>
Putting values of n
This function generates the given sequence.
<u>f(n) = 2(n − 1) − 3</u>
Putting values of n
This function doesn't generate the given sequence
<u>f(n) = 2(n − 1) + 3</u>
Putting values of n
Hence, the functions that produce given sequence are:
f(n) = 2n + 1
f(n) = 2(n − 1) + 3
Keywords: Functions, Sequence
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