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Simora [160]
3 years ago
15

In two or more complete sentences explain how to balance the chemical equation and classify its reaction type. ___NaI + ___Pb(SO

4)2 ⟶ ___PbI4 + ___Na2SO4
Chemistry
2 answers:
Fiesta28 [93]3 years ago
7 0
The balance would be 4nai + pb(so4)2 --> pbi4+ 2na2so4
Vsevolod [243]3 years ago
3 0

<u>Answer:</u> By applying law of conservation of mass.

<u>Explanation:</u>

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor can be destroyed but it can only be transformed from one form to another form.  

This law also states that the total number of individual atoms on the reactant side must be equal to the total number of individual atoms on the product side.

For the given reaction, the balanced chemical equation follows:

4NaI+Pb(SO_4)_2\rightarrow PbI_4+2Na_2SO_4

<u>On reactant side:</u>

Number of sodium atoms = 4

Number of iodine atoms = 4

Number of lead atoms = 1

Number of sulfur atoms = 2

Number of oxygen atoms = 8

<u>On product side:</u>

Number of sodium atoms = 4

Number of iodine atoms = 4

Number of lead atoms = 1

Number of sulfur atoms = 2

Number of oxygen atoms = 8

Hence, the balanced chemical equation is written above.

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You explored the relationship between molarity, the number of moles, and solution volume. However, when you prepare a solution,
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Answer:

2.64gram

Explanation:

Molarity, which refers to the molar concentration, is calculated thus:

Molarity = number of moles (n) ÷ volume (L)

According to the question, volume = 100 mL, molarity = 0.240 M.

Since 1L = 1000mL

100 mL = 100/1000

= 0.1L

Hence;

0.240 = n/0.1

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Air trapped in a cylinder fitted with a piston occupies 145 mL at 1.08 atm
pav-90 [236]

Answer: 0.0014 atm

Explanation:

Given that,

Original pressure of air (P1) = 1.08 atm

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Thus, the new pressure of air when the volume is decreased to 111 L is 0.0014 atm

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