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3 years ago

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Uranium-267 undergoes alpha decay, what is the mass of the new element?

1 answer:

Firlakuza [10]3 years ago

3 0

Answer:

will this help ?

Explanation:

(108Hs) is a synthetic element, and thus a standard atomic weight cannot be given. Like all synthetic elements, it has no stable isotopes. The first isotope to be synthesized was 265Hs in 1984. There are 12 known isotopes from 263Hs to 277Hs and 1–4 isomers. The most stable isotope of hassium cannot be determined based on existing data due to uncertainty that arises from the low number of measurements. The confidence interval of half-life of 269Hs corresponding to one standard deviation (the interval is ~68.3% likely to contain the actual value) is 16 ± 6 seconds, whereas that of 270Hs is 9 ± 4 seconds. It is also possible that 277mHs is more stable than both of these, with its half-life likely being 110 ± 70 seconds, but only one event of decay of this isotope has been registered as of 2016.[1][2].

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A chemist fills a reaction vessel with 7.92 atm nitrogen (N2) gas, 2.02 atm hydrogen (H2) gas, and 2.11 atm ammonia (NH3) gas at

djverab [1.8K]

<u>Answer:</u> The Gibbs free energy of the given reaction is -40 kJ

<u>Explanation:</u>

The given chemical equation follows:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

The equation for the standard Gibbs free change of the above reaction is:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(NH_3(g))})]-[(1\times \Delta G^o_f_{(N_2(g))})+(3\times \Delta G^o_f_{(H_2(g))})]$

We are given:

$\Delta G^o_f_{(NH_3(l))}=-16.45kJ/mol\\\Delta G^o_f_{(H_2(g))}=0kJ/mol\\\Delta G^o_f_{(N_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-16.45))]-[(1\times (0))+(3\times (0))]\\\\\Delta G^o_{rxn}=-32.9kJ/mol$

The equation used to Gibbs free energy of the reaction follows:

$\Delta G=\Delta G^o+RT\ln Q_{eq}$

where,

$\Delta G$ = free energy of the reaction

$\Delta G^o$ = standard Gibbs free energy = -32.9 kJ/mol = -32900 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = Temperature = $25^oC=[273+25]K=298K$

$Q_{eq}$ = Ratio of concentration of products and reactants at any time = $\frac{(p_{NH_3})^2}{(p_{H_2})^3\times p_{N_2}}$

$p_{NH_3}=2.11atm$

$p_{N_2}=7.92atm$

$p_{H_2}=2.02atm$

Putting values in above equation, we get:

$\Delta G=-32900J/mol+(8.314J/K.mol\times 298K\times \ln (\frac{(2.11)^2}{(2.02)^3\times 7.92}))\\\\\Delta G=-39553.04J/mol=--39.55kJ=-40kJ$

Hence, the Gibbs free energy of the given reaction is -40 kJ

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3 years ago

are medications typically used to relieve excessive mucus in nasal pathways. a) Radioactive isotopes b) Expectorants c) Deconges

Mrac [35]

Answer:

c) decongestants relive excessive muscle in nasal pathways

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3 years ago

Why are animals so impportant to our lifes

ivann1987 [24]

Answer:

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Explanation:

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2 years ago

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A horse pulls on a cart with a force of 1800 newtons. The cart accelerates at the rate of 4.39 m/s2. According to Newton's law o

AlladinOne [14]

Answer:

Answer = 410.02277904328

Explanation:

1,800 N * $4.39m/s^2$ = 410.02277904328 m

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3 years ago

How many atoms are in 2.2 moles of Zinc?

jenyasd209 [6]

There are 1 .5 million atoms in moles

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