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wolverine [178]
3 years ago
15

Solve using significant figures 8.647 + 45.969

Chemistry
2 answers:
marishachu [46]3 years ago
7 0

Answer:

54.62

Explanation:

When you are adding numbers the significant figures for the result must be the smallest number of significant figures from the numbers you are adding.

In this case, you have 8.647 with 4 significant figures

And 45.969 with 5 significant figures

So, your result must have 4 significant figures.

Now, when you add the numbers you obtain:

8.647+45.969 = 54.616

But this result has 5 significant figures, so you need to round to the next integer, in this case, you should round to the number 2 because the number to follow the 1 is greater than 5.

Then you have that 54.616 rounded to the next integer is 54.62 with 4 significatn figures.

Murrr4er [49]3 years ago
5 0

Answer:

54.616

Explanation:

8.647 + 45.969

or rewrite for easier look:

45.969 +

 8.647 =

54.616

Hope this helped :3

 

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The three mass value measure are precise mass

<u>explanation</u>

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6 0
3 years ago
What is Cytokine Release Syndrome (CRS)
laila [671]

Answer:

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Explanation:

4 0
3 years ago
Given the following data:N2(g) + O2(g)→ 2NO(g), ΔH=+180.7kJ2NO(g) + O2(g)→ 2NO2(g), ΔH=−113.1kJ2N2O(g) → 2N2(g) + O2(g), ΔH=−163
statuscvo [17]

Answer:

ΔH = +155.6 kJ

Explanation:

The Hess' Law states that the enthalpy of the overall reaction is the sum of the enthalpy of the step reactions. To do the addition of the reaction, we first must reorganize them, to disappear with the intermediaries (substances that are not presented in the overall reaction).

If the reaction is inverted, the signal of the enthalpy changes, and if its multiplied by a constant, the enthalpy must be multiplied by the same constant. Thus:

N₂(g) + O₂(g) → 2NO(g) ΔH = +180.7 kJ

2NO(g) + O₂(g) → 2NO₂(g) ΔH = -113.1 kJ

2N₂O(g) → 2N₂(g) + O₂(g) ΔH = -163.2 kJ

The intermediares are N₂ and O₂, thus, reorganizing the reactions:

N₂(g) + O₂(g) → 2NO(g) ΔH = +180.7 kJ

NO₂(g) → NO(g) + (1/2)O₂(g) ΔH = +56.55 kJ (inverted and multiplied by 1/2)

N₂O(g) → N₂(g) + (1/2)O₂(g) ΔH = -81.6 kJ (multiplied by 1/2)

------------------------------------------------------------------------------------

N₂O(g) + NO₂(g) → 3NO(g)

ΔH = +180.7 + 56.55 - 81.6

ΔH = +155.6 kJ

5 0
3 years ago
Why is true about electron dot diagrams
vazorg [7]

Answer: The correct answer is the option: B. An element with eight valence electrons is chemically unstable.

Explanation:

Hello! Let's solve this!

We will analyze each of the options:

A. The group number of the element provides a clue to the number of valence electrons: it is correct, since it provides the number of valence electrons.

B. An element with eight valence electrons is chemically unstable: this is not correct, since elements with eight electrons in the valence shell cannot react because they already have the last complete shell. Therefore, they are chemically stable.

C. The points must be placed one at a time on each side of the chemical symbol: it is correct, because that is the way to make the point diagram.

D. An atom is chemically stable if all the points are paired: this is correct since this verifies that the point diagram has been done well.

We conclude that the correct answer is the option: B. An element with eight valence electrons is chemically unstable.

Hope this helps.....  Stay safe and have a Merry Christmas!!!!!!!!! :D

7 0
3 years ago
BRAINLIEST ANSWER _ A balloon occupies a volume of 0.93 liters at a pressure of 84.5 kPa. When the balloon is allowed to expand
SVEN [57.7K]
V1 = 2.0 L T1 = 25.0 oC = 298 K V2 = V1T2 = (2.0 L)(244 K) = 1.6 L V2 = ? t1(298 K) T2 = –28.9 oC = 244 K
 
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