Answer:
He needs 5x+56 ft
Step-by-step explanation:
To find how much of fencing he needs , we find the perimeter of the given figure
All sides are equal in a square
To find perimeter of the square we add all the sides
4 sides we have for the square
one side is x, so perimeter of square = x+x+x+x= 4x
Now we find perimeter of rectangle
Opposite sides of rectangle are equal
Here for rectangle we consider only three sides
because fourth side is common for rectangle and square
So perimeter of the rectangle (with 3 sides) = 28 +x+ 28 = 56+x
Total fencing = perimeter of square + perimeter of rectangle
4x + 56 + x= 5x+56
<span>Table:
Class Boundaries Frequency
5-10 8
10-15 9
15-20 15
20-25 10
25-30 8
30-35 6
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total 56
Average =
[5+10]/2*8+[10+15]/2*9+[15+20]/2*15+[20+25]/2*10+[25+30]/2*8+[30+35]/2*6
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</span> 56
That is 1075 / 56 = 19.2
Answer: 19
We can use the same equation to figure out with only substituting the amount he was paid per photo.
Site A y = $0.85x = $0.85(5) = $4.25
Site B y = $0.40x = $0.40(5) = $2.00
We can see that Jim was paid $2.25 more at site A than Site B.
$r=3958. 13$ miles good luck in college a student from middle school
