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Grace [21]
3 years ago
14

Verify the identity Cos^2x-Sin^2x=1-2sin^2x

Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0
Cos^2x-Sin^2x=1-2sin^2x  \\  Cos^2x-Sin^2=cos(2x) \\ 1-2sin^2=cos2x \\ cos(2x) =cos2x \\   \\ \\ Cos^2x-Sin^2x=1-2sin^2x  \\ \mathrm{cos^2x+sin^2x=1 ~~~\Rightarrow ~~cos^2x=1-sin^2x} } \\ 1-sin^2x-sin^2x=1-2sin^2x \\ 1-2sin^2x=1-2sin^2x
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Hi, searching I found the image for the question, attached down below.

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4 years ago
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