Tanya flipped a coin and got heads 7 out of 10
1 answer:
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Question 1: Equiangular
Question 2: Area of the parallelogram = 48 square centimeters
Question 3: Perimeter of the rectangle = 42 ft
Question 4: Area of the trapezoid = 154 square inches
Solution:
Question 1:
The given polygon is a rectangle.
The angles of each side of the polygon is 90°.
This means all angles are equal.
Hence Option A equiangular is the correct answer.
Question 2:
Area of the parallelogram = Base × Height]
= 6 cm × 8 cm
Area of the parallelogram = 48 square centimeters
Question 3:
Perimeter of the rectangle = 2(length + width)
= 2( 15 ft + 6 ft)
= 2(21 ft)
Perimeter of the rectangle = 42 ft
Question 4:
Area of the trapezoid =
Area of the trapezoid = 154 square inches
Answer:
2/7 ml
Step-by-step explanation:
When we have a solution expressed in Q mg/ml, the concentration is (Q/10)%.
For example, a solution of 3 mg/ml is a 3/10=0.3% concentration solution, a solution of 40 mg/ml is a 40/10=4% concentration solution.
<em>Why? </em>
Q mg/ml means that 1 ml of solution has Q mg of the drug or active component. So, 100 ml have 100*Q mg.
But 100*Q mg = Q/10 grams.
If a solution has Q/10 grams in 100 ml, then it is a (Q/10)% concentration.
Now, we have 5 ml of a solution that contains tobramycin, 3 mg/ml (each ml has 3 mg of tobramycin).
This means that the 5 ml contain 15 mg of tobramycin.
On the other hand, we have another solution S containing 40 mg/ml of tobramycin. This means that each ml of S contains 40 mg of tobramycin.
Let x be the amount of ml of S we have to add to our first 5 ml.
If 1 ml of S contains 40 mg of tobramycin, x ml contain 40*x mg.
If we add this x ml to our first 5 ml, we have 5+x ml containing 15+40*x mg of tobramycin.
Now, cross-multiply to get how much tobramycin contains 1 ml of this new solution.
5+x ml ____contain____15+40*x mg of tobramycin
1 ml ____contains____? mg
And we have
as a result, we have a solution of
We want to prepare a solution 0.5% in concentration.
Using what we state at the beginning, we need to find a value x such that
solving for x
So, we have to add just 2/7 ml of the stronger solution.