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3 years ago

Abby has 45 marbles she has five times as many marbles as Joe has how many marbles does Joe have

Mathematics

2 answers:

ivolga24 [154]3 years ago

3 0

45÷5 is 9 so that means joe has only 9 marbles

levacccp [35]3 years ago

3 0

45 divided by 5 = 9 he has 9 marbles

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John is putting a fence around his garden that is shaped like a half circle and a rectangle. A rectangle has a length of 14 feet

charle [14.2K]

Answer:

Area of the garden = 98 + 19.25 = 117.25 ft²

Step-by-step explanation:

Area of the garden = area of the rectangle + area of the semi-circle

Area of the rectangle = L x B = 14 x 7 = 98 ft²

Area of the semi-circle = 1/2 x πR² = 1/2 x 22/7 x 3.5² = 19.25 ft²

Hence area of the garden = 98 + 19.25 = 117.25 ft²

6 0

3 years ago

Given the following functions, find each of the values:

allsm [11]

The function is computed below based on the information. The answers will be:

1. -11

2. -1

<h3>How to compute the function?</h3>

f(x) = x²-11x+28

g(x) = x-4

(f+g)(-5) = (-5² - 11 × 5 + 28) + (-5 - 4)

= 25 - 55 + 28 - 9

= -11

(f-g)(5)

= = (5² - 11 × 5 + 28) + (5 - 4)

= 25 - 55 + 28 + 1

= -1

Learn more about functions on:

brainly.com/question/25638609

#SPJ1

4 0

1 year ago

The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the imprope

lesya692 [45]

(1) D

$L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt$

Integrate by parts, taking

$u = t \implies \mathrm du=\mathrm dt$

$\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}$

Then

$L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}$

(2) A

$L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt$

$L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}$

$L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}$

7 0

3 years ago

Select the correct answer.

FrozenT [24]

Shouldn't the equation read " (x - 4)² = 81 ", instead of "(1 - 4)² = 81" ?

If so, then the solutions are x = -5 and x = 13 .

If it's really "(1 - 4)² = 81", then that's not even an equation, and there's no solution.

3 0

3 years ago

Please help if you can

Arisa [49]

Answer:

Option D

Step-by-step explanation:

Formula to be used,

Scale factor = $\frac{\text{Dimension of the image rectangle}}{\text{Dimension of the original}}$

By this formula,

$\frac{7}{2}=\frac{\text{Length of the dilated rectangle}}{\text{Length of the original rectangle}}$

$\frac{7}{2}=\frac{L}{22}$

L = $\frac{7\times 22}{2}$

= 77 inches

Similarly, width of the the dilated rectangle = $\frac{7}{2}\times 10$

= 35 inches

Perimeter of the new rectangle = 2(Length + width)

= 2(77 + 35)

= 224 inches

Option (D) will be the correct option.

7 0

3 years ago