Capacity of the hard drive = 160 GB.
Used space = 122 GB.
Free space = 160 - 122 = 38 GB.
So, the size of the home video collection should be less than or equal to 38 GB.
If u is the amount of space used, then, u ≤ 38
If a is the amount of space available, then a = 38 - u.
Answer:-30
Step-by-step explanation:
Third term=a3
an=a(n-1) x (-9)
a3=5/3 x (3-1) x (-9)
a3=5/3 x 2 x -9
a3=(5x2x-9)/3
a3=-90/3
a3=-30
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
(y2-y1)/(x2-x1)=
slope: 21/26
Answer:
there are no other ratios shown but 8:6,12:9,16:12,20:15,and 24:18 are all equivalent
Step-by-step explanation:
smile time