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Vladimir79 [104]
4 years ago
9

BWI Airport is building a new parking lot. The parking lot will need to fit 1350 cars. A typical row of parking spaces has 30 sp

aces. How many rows have to be built to hold 1350 cars? Rather than build rows that fit 30 cars, the airport is requesting rows that fit 50 cars. How many fewer rows are needed if the rows fit 50 card?
Mathematics
1 answer:
Evgesh-ka [11]4 years ago
8 0

Answer:

45 rows will need to be built to hold 1350 cars. (for 30 spaces a row)

19 fewer rows are needed if the rows fit 50 cars (for the 50 spaces a row)

Step-by-step explanation:

for the first question divide 1350 by 30 and the second divide 1350 by 50, good luck!

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Which best describe the relationship between the two lines describe below?
Anna007 [38]

we have

6x+3y=12 -----> line p

Find the slope

3y=-6x+12

y=-2x+4

m=-2

-4x=2y-2 -----> line Q

2y=-4x+2

y=-2x+1

m=-2

therefore

the lines are parallel because their slopes are equal

7 0
1 year ago
Jerry’s rhombus has a base of 15 inches and a height of 9 inches. Charlene’s rhombus has a base and a height that are 13 the bas
neonofarm [45]

Answer:  The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

Step-by-step explanation:

I will assume that the exercise says "\frac{1}{3} times the base and height of Jerry’s rhombus".

The area of a rhombus can be calculated with the following formula:

A=b*a

Where "b" is the length of the base  and "a" is the altitude or the height.

Then, you can calculate the area using the formula shown above.

Therefore, you get:

1. Jerry's rhombus:

A_1=(15\ in)(9\ in)\\\\A_1=135\ in^2

2. Charlene's rhombus:

A_2=(\frac{1}{3}*15\ in)(\frac{1}{3}*9\ in)\\\\A_2=(5\ in)(3\ in)\\\\A_2=15\ in^2

Dividing the area calculated, you get:

\frac{135\ in^2}{15\ in^2}=9

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

7 0
4 years ago
Read 2 more answers
Brenna is a makeup artist and carries a lot of makeup around with her. She has 16 cosmetics
damaskus [11]

Answer:

4/16

Step-by-step explanation:

7 0
3 years ago
Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc
drek231 [11]

Answer:

C. 178−−−√ m

Step-by-step explanation:

Given the following :

v = final velocity (in m/s)

u = initial velocity (in m/s)

a = acceleration (in m/s²)

s = distance (in meters).

Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters

Using the 3rd equation of motion :

v^2 = u^2 + 2as

v^2 = 8^2 + 2(3)(19)

v^2 = 64 + 114

v^2 = 178

Take the square root of both sides :

√v^2 = √178

v = √178

6 0
3 years ago
I’ve got this and one more!!!
lisabon 2012 [21]

Area:500{  m}^{2}

5 0
3 years ago
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