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Vladimir79 [104]
3 years ago
9

BWI Airport is building a new parking lot. The parking lot will need to fit 1350 cars. A typical row of parking spaces has 30 sp

aces. How many rows have to be built to hold 1350 cars? Rather than build rows that fit 30 cars, the airport is requesting rows that fit 50 cars. How many fewer rows are needed if the rows fit 50 card?
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0

Answer:

45 rows will need to be built to hold 1350 cars. (for 30 spaces a row)

19 fewer rows are needed if the rows fit 50 cars (for the 50 spaces a row)

Step-by-step explanation:

for the first question divide 1350 by 30 and the second divide 1350 by 50, good luck!

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A seamstress uses 12 yards of fabric to make 3 costumes for students in the chorus. How many yards will she need to make costume
KIM [24]

Answer:

100 yards of fabric

Step-by-step explanation:

12 divided by 3 = 4 yards of fabric per costume

4 x 25 = 100 yards of fabric

4 0
3 years ago
3.18x+2.6+0.9x+x=28<br> Solve please, brainliest will be awarded
Elis [28]

Answer:

x=5

Step-by-step explanation

3.18x+2.6+0.9x+x=28

3.18x+0.9x+x+2.6=28

5.08x+2.6=28

5.08x+2.6-2.6=28-2.6

5.08x=25.4

x=5

hope it helps

8 0
3 years ago
Read 2 more answers
Find the surface area of the following figure.
fgiga [73]

Answer:

\boxed{\textsf{\pink{ Hence the TSA of the cuboid is $\sf 32x^2$}}}.

Step-by-step explanation:

A 3D figure is given to us and we need to find the Total Surface area of the 3D figure . So ,

From the cuboid we can see that there are 5 squares in one row on the front face . And there are two rows. So the number of squares on the front face will be 5*2 = 10 .

We know the area of square as ,

\qquad\boxed{\sf Area_{(square)}= side^2}

Hence the area of 10 squares will be 10x² , where x is the side length of each square. Similarly there are 10 squares at the back . Hence their area will be 10x² .

Also there are in total 12 squares sideways 6 on each sides . So their surface area will be 12x² . Hence the total surface area in terms of side of square will be ,

\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies\boxed{\sf TSA_{(cuboid)}= 32x^2}

Now let's find out the TSA in terms of side . So here the lenght of the cuboid is equal to the sum of one of the sides of 5 squares .

\sf\implies 5x = l \\\\\sf\implies x = \dfrac{l}{5} \\\\\qquad\qquad\underline\red{ \sf Similarly \ breadth }\\\\\sf\implies b = 3x  \\\\\sf\implies x = \dfrac{ b}{3}

\rule{200}2

Hence the TSA of cuboid in terms of lenght and breadth is :-

\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies TSA_{(cuboid)}= 20\bigg(\dfrac{l}{5}\bigg)^2+12\bigg(\dfrac{b}{3}\bigg) \\\\\sf\implies TSA_{(cuboid)}= 20\times\dfrac{l^2}{25}+12\times \dfrac{b^2}{9}\\\\\sf\implies \boxed{\red{\sf TSA_{(cuboid)}= \dfrac{4}{5}l^2 +\dfrac{4}{3}b^2 }}

6 0
2 years ago
If the data analyst hypothesizes that grocery sales are lower on Sunday than on other days, the null hypothesis would likely sta
nlexa [21]

Answer:

The answer is "Grocery sales are lower or no different on Sunday than on other days"

Step-by-step explanation:

Its null hypothesis does not always consider any discrepancy between both the comparable qualities throughout facts and figures. Furthermore, researchers recommend also have lower or even no opposite transactions for Sunday than with other days, because there is no connection between grocery sales and Saturdays and Sundays.

7 0
3 years ago
When Ricardo was 9 years old, he was 56 inches tall. Ricardo is now 12 years old and he is 62 inches tall. Find the percent of i
Lena [83]
Explanation:
The formula for calculating the percent change in a value between two points in time is:
p
=
N
−
O
O
⋅
100
Where:
p
is the percent change - what we are solving for in this problem.
N
is the New Value - 62 inches in this problem.
O
is the Old Value - 56 inches in this problem.
Substituting and solving for
p
gives:
p
=
62
−
56
56
⋅
100
p
=
6
56
⋅
100
p
=
600
56
p
=
10.7
rounded to the nearest tenth.
Ricardo gres 10.7%
5 0
3 years ago
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